互转的前提是属性名相同,如果属性名不同,又要互转,只能自已手写工具类了 1、pom
xml
<dependency>
<groupId>commons-beanutils</groupId>
<artifactId>commons-beanutils</artifactId>
<version>1.9.4</version>
</dependency>
2、map转实体类,如果属性里有list会出错
ini
Map<String, String> of = ImmutableMap.of("a", "aaaaa", "b", "kluowejbbbb");
Student student = new Student();
BeanUtils.copyProperties(student,of);
DTO转VO
ini
StudentVO studentVO = new StudentVO();
studentVO.setAge("sdfsafd");
studentVO.setStudentName("jkljsie");
StudentDTO studentDTO = new StudentDTO();
BeanUtils.copyProperties(studentDTO, studentVO);
System.out.println("studentDTO = " + studentDTO); // {studentName='jkljsie', age='sdfsafd'}
DTO转map,如果属性里有list会出错
ini
StudentVO studentVO = new StudentVO();
studentVO.setAge(12);
studentVO.setStudentName("jkljsie");
Map<String, String> describe = BeanUtils.describe(studentVO); // 如果属性里有list会出错
也可以用fastjson去转换 1、pom
xml
<dependency>
<groupId>com.alibaba</groupId>
<artifactId>fastjson</artifactId>
<version>1.2.69</version>
</dependency>
2、先成转json再转成dto
javascript
StudentVO studentVO = new StudentVO(12,"aaaaaa");
String s = JSONObject.toJSONString(studentVO);
StudentDTO studentDTO = JSONObject.parseObject(s, StudentDTO.class);
System.out.println("studentDTO = " + studentDTO); // {studentName='aaaaaa', age='12'}
// 转成map
Map<String,String> hashMap = JSONObject.parseObject(map, HashMap.class);