map实现
为什么用map而不用{...}
- map不仅能存储, 还有顺序
- {...}只能存储, 没有顺序
            
            
              js
              
              
            
          
          class LRU {
  private maxLength = 1;
  private hash = new Map();
  constructor(length = 1) {
    if (length < 1) throw new Error("length 不能小于1");
    this.maxLength = length;
  }
  set(key: any, value: any) {
    if (this.hash.has(key)) {
      this.hash.delete(key);
    }
    this.hash.set(key, value);
    if (this.hash.size > this.maxLength) {
      const oldestKey = this.hash.keys().next().value;
      this.hash.delete(oldestKey);
    }
  }
  get(key: any) {
    const v = this.hash.get(key);
    this.hash.delete(key);
    this.hash.set(key, v);
    return v;
  }
}测试: set更新排序
            
            
              js
              
              
            
          
          const lru = new LRU(2);
lru.set(1, 100);
lru.set(2, 200);
lru.set(1, 101);
lru.set(3, 300);
console.log(lru.get(1)); // 101
console.log(lru.get(2)); // undefined
console.log(lru.get(3)); // 300测试: get更新排序
            
            
              js
              
              
            
          
          const lru = new LRU(2);
lru.set(1, 100);
lru.set(2, 200);
lru.get(1);
lru.set(3, 300);
console.log(lru.get(1)); // 100
console.log(lru.get(2)); // undefined
console.log(lru.get(3)); // 300双向链表
- 用双向链表仿了一个MyMap
- 如何仿一个map
- 既能快速查询hash[key]
- 又能有顺序
 
- 既能快速查询
            
            
              js
              
              
            
          
          // 下面是MyMap的数据结构
// 既能快速查询, 又有顺序
const hash = {
    key1: item1 
            🔽   // item1.next = item2
    key2: item2
            🔽   // item2.next = item3
    key3: item3
            🔽   // item3.next = item4
    key4: item4
            🔽   // item4.next = item5
    key5: item5
}代码实现
            
            
              js
              
              
            
          
          class LRU {
  private maxLength = 1;
  private hash = new MyMap();
  constructor(length = 1) {
    if (length < 1) throw new Error("length 不能小于1");
    this.maxLength = length;
  }
  set(key: any, value: any) {
    if (this.hash.has(key)) {
      this.hash.delete(key);
    }
    this.hash.set(key, value);
    if (this.hash.size > this.maxLength) {
      const oldestKey = this.hash.head?.key;
      this.hash.delete(oldestKey);
    }
  }
  get(key: any) {
    const v = this.hash.get(key);
    this.hash.delete(key);
    this.hash.set(key, v);
    return v;
  }
}
class ListNode {
  key: string;
  value: any;
  next: ListNode | null = null;
  prev: ListNode | null = null;
  constructor(key: string, value: any) {
    this.key = key;
    this.value = value;
  }
}
class MyMap {
  data: { [key: string]: ListNode } = {};
  size: number = 0;
  head: ListNode | null = null;
  tail: ListNode | null = null;
  has(key: string) {
    return this.data[key] ? true : false;
  }
  // 移动到末尾, 末尾是最新鲜的
  move2Tail(node: ListNode) {
    if (this.tail === node) return; // 已经是最新鲜的了
    node = this.cut(node);
    const prevNode = this.tail;
    if (prevNode) prevNode.next = node;
    node.prev = prevNode;
    this.tail = node;
  }
  add(node: ListNode) {
    this.move2Tail(node);
    this.data[node.key] = node;
    this.size++;
    if (this.size === 1) this.head = node; // 添加的第一个
  }
  delete(key?: string) {
    if (!key) return;
    const node = this.data[key];
    if (node) this.cut(node);
    delete this.data[key];
    this.size--;
  }
  get(key: string) {
    const target = this.data[key];
    if (!target) return;
    // 末尾的是最新鲜的
    if (target !== this.tail) {
      this.move2Tail(target);
    }
    return target.value;
  }
  set(key: string, value: any) {
    const target = this.data[key];
    if (!target) {
      const newNode = new ListNode(key, value);
      this.add(newNode);
    } else {
      target.value = value;
      this.move2Tail(target);
    }
  }
  cut(node: ListNode) {
    const preNode = node.prev;
    const nextNode = node.next;
    if (this.head === node) {
      this.head = node.next;
    }
    if (this.tail === node) {
      this.tail = node.prev;
    }
    if (preNode) preNode.next = nextNode;
    if (nextNode) nextNode.prev = preNode;
    node.prev = null;
    node.next = null;
    return node;
  }
}