C语言完美演绎7-5

/* 范例：7-5 */

#include <stdio.h>

int main()

{

/* 定义四个字符类型的变量 */

char GetVarAddress1;

char GetVarAddress2;

char GetVarAddress3;

char GetVarAddress4;

/* 指派四个字符变量的内容值 */

GetVarAddress1 = 'g';

GetVarAddress2 = 'o';

GetVarAddress3 = 'o';

GetVarAddress4 = 'd';

/* 取得四个字符变量的地址，并输出至屏幕 */

printf("\nGetVarAddress1变量在记忆中的地址是%d",&GetVarAddress1);

printf("\nGetVarAddress2变量在记忆中的地址是%d",&GetVarAddress2);

printf("\nGetVarAddress3变量在记忆中的地址是%d",&GetVarAddress3);

printf("\nGetVarAddress4变量在记忆中的地址是%d",&GetVarAddress4);

printf("\n\n%c%c%c%c", GetVarAddress1, GetVarAddress2, \

GetVarAddress3,GetVarAddress4);

getchar();

return 0;

}

程序执行结果：

GetVarAddress1变量在记忆中的地址是6618627

GetVarAddress2变量在记忆中的地址是6618626

GetVarAddress3变量在记忆中的地址是6618625

GetVarAddress4变量在记忆中的地址是6618624

good