/* 范例：9-16（以VC++执行，请参考范例光盘源代码中的说明）*/
#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
struct person
{
char name30;
int age;
person *next;
};
person *start, *nowper, *newper; /* 步骤一 */
void main(void)
{
char agestr5; /* 年龄以字符串方式输入 */
clrscr(); /* 清屏 */
do
{
newper = (person *)malloc(sizeof(person));
if (start==0) /* 步骤二 */
start = nowper = newper;
else
{
nowper = start; /* 将目前指针指向开头 */
while(nowper->next != (person *)NULL)
nowper = nowper->next ; /* 找链表尾端 */
nowper->next = newper; /* 将原链表尾指向新节点 */
nowper = newper;
}
printf("\n输入姓名:"); gets(nowper->name);
printf("\n输入年龄:"); gets(agestr);
nowper->age = atoi(agestr);
nowper->next = (person *)NULL; /* 链表尾端指向NULL */
printf("是否继续 是(y)否(n)? ");
}while(getche()!='n');
nowper = start; /* 从头输出 */
clrscr();
do
{
printf("\n姓名:%s 年龄: %d", \
nowper->name,nowper->age);
nowper = nowper->next ; /* 移到下一节点输出 */
}while(nowper != (person *)NULL);
getchar();
}