【PAT甲级真题】- Spell It Right(20)

paeamecium2026-05-08 8:49

题目来源

题目描述点击链接自行查看

注意点：

末尾无空格，多换一行

Description

Given a non-negative integer N N N, your task is to compute the sum of all the digits of N N N, and output every digit of the sum in English.

Input Specification:

Each input file contains one test case. Each case occupies one line which contains an N ( ≤ 10 100 ) N (≤10 ^{100}) N(≤10100).

Output Specification:

For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.

Sample Input:

复制代码

Sample Output:

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one five

题目大意

给出一个很大的整数 N N N ，计算它每个位的数字之和，然后从左到右，输出这个和的每个位的数字对应的英文

思路简介

一道打表题

对于数字转字母的处理就用一个字符串数组打表

cpp 复制代码

string dig[]={
    "zero","one","two","three",
    "four","five","six","seven",
    "eight","nine"
};

输入记得输字符串，整数无法直接输入， $10\^{100}$ 超出范围了

求和时，数字字符减去 '0' 即为其数字的数值

求和后对照表输出即可

遇到的问题

无，一遍过

代码

cpp 复制代码

/**
 * https://pintia.cn/problem-sets/994805342720868352/exam/problems/type/7?problemSetProblemId=994805519074574336
 * 打表
 */
#include<bits/stdc++.h>
using namespace std;

string dig[]={
    "zero","one","two","three",
    "four","five","six","seven",
    "eight","nine"
};

void solve(){
    string n;cin>>n;   
    int sum=0;
    for(auto x:n){
        sum+=x-'0';
    }
    string res=to_string(sum);
    int len=res.size();
    for(int i=0;i<len;++i){
        cout<<dig[res[i]-'0'];
        if(i!=len-1)cout<<' ';
    }
    cout<<'\n';
}

int main(){
    ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
    //fstream in("in.txt",ios::in);cin.rdbuf(in.rdbuf());
    int T=1;
    //cin>>T;
    while(T--){
        solve();
    }
    return 0;
}