Jackson 解决没有无参构造函数的反序列化问题

文章目录

1. 问题

在对外部代码或项目中明确不能提供无参构造函数的实例进行反序列化时,Jackson 会报找不到构造器的错误提示信息。那么如何在不修改代码的前提下实现反序列呢?

2. 解决方案

2.1 实现反序列化器

Response

Response 对象没有提供无参构造函数,但是要实现反序列化功能。

java 复制代码
@Setter
@Getter
public class Response {
    private Map<String, String> headerMap;
    private Map<String, String> apiMap;

    public Response(Map<String, String> headerMap, Map<String, String> apiMap) {
        this.headerMap = headerMap;
        this.apiMap = apiMap;
    }
}
ResponseDeserializer

此时,可以通过实现 JsonDeserializer<Response> 接口,实现自定义反序列化器。

java 复制代码
public class ResponseDeserializer extends JsonDeserializer<Response> {
    @Override
    public Response deserialize(JsonParser jsonParser, DeserializationContext deserializationContext) throws IOException {
        Map<String, Map<String, String>> map = jsonParser.readValueAs(Map.class);
        Map<String, String> headerMap = map.get("headerMap");
        Map<String, String> apiMap = map.get("apiMap");

        return new Response(headerMap, apiMap);
    }
}
ObjectMapperUtil

将反序列化器注册到 ObjectMapper 中:

java 复制代码
public class ObjectMapperUtil {
    private static ObjectMapper objectMapper = new ObjectMapper();

    static {
        SimpleModule simpleModule = new SimpleModule("custom");
        simpleModule.addDeserializer(Response.class, new ResponseDeserializer());
        objectMapper.registerModule(simpleModule);
    }

    public static ObjectMapper getObjectMapper() {
        return objectMapper;
    }

    /**
     *
     * @param object
     * @return
     */
    public static String writeAsPrettyString(Object object) {
        try {
            return getObjectMapper().writerWithDefaultPrettyPrinter().writeValueAsString(object);
        } catch (JsonProcessingException e) {
            e.printStackTrace();
        }
        return null;
    }
}

2.2 通过 MIXMIN 和 @JsonCreator机制实现

ResponseMixin

首先实现 @JsonCreator 功能的构造器:

java 复制代码
public class ResponseMixin {
    @JsonCreator
    public ResponseMixin(@JsonProperty("headerMap")Map<String, String> headerMap,
                         @JsonProperty("apiMap")Map<String, String> apiMap) {
    }
}

3. 测试

ResponseTest
java 复制代码
// Jackson 解决没有无参构造函数的反序列化问题 - https://segmentfault.com/a/1190000041734426
public class ResponseTest {

    @Test
    public void testUseSelfDeserializeWithoutNoArgsConstructor() throws JsonProcessingException {
        Map<String, String> headerMap = new HashMap<>();
        headerMap.put("Content-Type", "application/json");
        headerMap.put("Content-Length", "123");
        Map<String, String> apiMap = new HashMap<>();
        apiMap.put("user", "用户");
        apiMap.put("admin", "管理员");
        Response response = new Response(headerMap, apiMap);
        String jsonStr = ObjectMapperUtil.getObjectMapper().writeValueAsString(response);
        System.out.println(jsonStr);

        response = ObjectMapperUtil.getObjectMapper().readValue(jsonStr, Response.class);
        System.out.println(response != null);
    }
    @Test
    public void testUseMixin() throws JsonProcessingException {
        ObjectMapper objectMapper = new ObjectMapper();
        objectMapper.addMixIn(Response.class, ResponseMixin.class);

        Map<String, String> headerMap = new HashMap<>();
        headerMap.put("Content-Type", "application/json");
        headerMap.put("Content-Length", "123");
        Map<String, String> apiMap = new HashMap<>();
        apiMap.put("user", "用户");
        apiMap.put("admin", "管理员");
        Response response = new Response(headerMap, apiMap);
        String jsonStr = objectMapper.writeValueAsString(response);
        System.out.println(jsonStr);

        response = objectMapper.readValue(jsonStr, Response.class);
        System.out.println(response != null);
    }
}
相关推荐
zhanghaofaowhrql14 小时前
Spring Data JPA Repository 详解:从基础到高级用法
java·数据库·sql
编程(变成)小辣鸡15 小时前
如何防止接口被恶意刷?
java·后端·网络安全
大圣编程20 小时前
Java 多维数组详解
java·开发语言
万法若空1 天前
【算法-查找】查找算法
java·数据结构·算法
HZZD_HZZD1 天前
DL/T 645-2026新国标深度解读与智能电表协议适配实战:从帧结构变化到Java采集器升级的全链路改造方案
java·开发语言
山登绝顶我为峰 3(^v^)31 天前
C/C++ 交叉编译方法
java·c语言·c++
一叶飘零_sweeeet1 天前
Codex 与 Claude Code 深度拆解:两代 AI 编程智能体的技术本质与 Java 实战指南
java·ai·codex·claude code
Listen·Rain1 天前
提示词和提示词模板
java·人工智能·spring boot
wuqingshun3141591 天前
重写equals而不重写hashCode,会出什么问题?
java·开发语言