hdlbits

stm 学习ing3 天前
c语言·fpga开发·fpga·eda·hdlbits·pld·hdl语言
HDLBits训练5时间：2024.12.24这段代码实现了一个 4 - 位 BCD 计数器。每个十进制数位由 4 位二进制数表示。代码中定义了 4 个一位的 BCD 计数器（bcd0、bcd1、bcd2和bcd3）分别代表个位、十位、百位和千位。
卡布达吃西瓜1 年前
fpga开发·verilog·hdlbits
Verilog刷题[hdlbits] ：Always nolatchesSuppose you’re building a circuit to process scancodes from a PS/2 keyboard for a game. Given the last two bytes of scancodes received, you need to indicate whether one of the arrow keys on the keyboard have been pressed. This involves a fairly simple map
卡布达吃西瓜1 年前
fpga开发·verilog·hdlbits
Verilog刷题[hdlbits] ：Alwaysblock1Since digital circuits are composed of logic gates connected with wires, any circuit can be expressed as some combination of modules and assign statements. However, sometimes this is not the most convenient way to describe the circuit. Procedures (of whic
卡布达吃西瓜1 年前
fpga开发·verilog·hdlbits
Verilog刷题[hdlbits] ：Module addsubAn adder-subtractor can be built from an adder by optionally negating one of the inputs, which is equivalent to inverting the input then adding 1. The net result is a circuit that can do two operations: (a + b + 0) and (a + ~b + 1). See Wikipedia if you w
卡布达吃西瓜1 年前
fpga开发·verilog·hdlbits
Verilog刷题[hdlbits] ：Module cseladdOne drawback of the ripple carry adder (See previous exercise) is that the delay for an adder to compute the carry out (from the carry-in, in the worst case) is fairly slow, and the second-stage adder cannot begin computing its carry-out until the first-s
卡布达吃西瓜1 年前
fpga开发·verilog·hdlbits
Verilog刷题[hdlbits] ：Module addYou are given a module add16 that performs a 16-bit addition. Instantiate two of them to create a 32-bit adder. One add16 module computes the lower 16 bits of the addition result, while the second add16 module computes the upper 16 bits of the result, aft