Rust- 变量绑定

In Rust, you bind values to a variable name using the let keyword. This is often referred to as "variable binding" because it's like binding a name to a value.

Here's a simple example:

rust 复制代码
let x = 5;

In this example, x is bound to the value 5. By default, bindings are immutable in Rust. If you try to reassign x to a different value, you'll get a compile-time error. If you want a binding to be mutable, you can use the mut keyword:

rust 复制代码
let mut x = 5;
x = 10; // This is okay because x is mutable

In Rust, you can also bind a variable to an expression. The expression will be evaluated, and the resulting value will be bound to the variable:

rust 复制代码
let x = 5 * 5; // x is bound to the value 25

Variable binding in Rust also allows for pattern matching, which enables more complex types of binding. For example, if you have a tuple, you can bind the individual elements of the tuple to different variables:

rust 复制代码
let (x, y) = (1, 2); // x is bound to 1, and y is bound to 2

Rust also requires that all variables be initialized before they are used, which prevents undefined behavior.

Lastly, Rust features a system of "shadowing" where a new variable can be declared with the name of a previous variable, effectively creating a new variable that "shadows" the old one.

rust 复制代码
let x = 5;
let x = x + 5; // x is now 10
let x = x * 2; // x is now 20

Each x is a new variable that shadows the previous x. This is not the same as mutation because these xs are new variables, they just happen to have the same name as the previous variable.

rust 复制代码
fn main() {
    /*
        变量是有作用域的,也就是在一个代码块中生存。
        代码块 {}, 也允许变量遮蔽。
     */

    // main 函数中
    let spend = 1;
    {
        // 只存在本代码块中
        let target = "面向对象";
        println!("内部 {}", target);    // 内部 面向对象

        // 遮蔽了外面的spend
        let spend = 2.0;
        println!("内部 {}", spend);     // 内部 2
    }

    // target在此作用域是不存在的
    // println!("外部 {}", target);
    println!("外部 {}", spend);         // 外部 1

    // 遮蔽了spend
    let spend = String::from("学习时间1小时");
    println!("外部 {}", spend);         // 外部 学习时间1小时

    let spend2;
    {
        let x = 2;
        spend2 = x * x;
    }
    println!("spend2: {}", spend2);     // spend2: 4

    let spend3;
    // println!("spend3: {}", spend3); // 报错,使用了未初始化的绑定
    spend3 = 1;
    println!("another binding spend3: {}", spend3); // another binding spend3: 1

    // 冻结 资源存在使用的引用时,在当前作用域中这一资源是不可被修改的。
    let mut spend4 = Box::new(1);
    let spend5 = &spend4;   // `spend4` is borrowed here
    spend4 = Box::new(100); // `spend4` is assigned to here but it was already borrowed
    println!("{}", spend4);
    println!("{}", spend5);
}
相关推荐
csdn_life184 小时前
Rustrover 如何像Java一样直接 进行调试和运行
java·开发语言·rust
Source.Liu14 小时前
【time-rs】Date 结构体详解
rust·time
qq_256247051 天前
Rust 模块化单体架构:告别全局 Migrations,实现真正的模块自治
开发语言·架构·rust
分布式存储与RustFS1 天前
MinIO替代方案与团队适配性分析:RustFS如何匹配不同规模团队?
人工智能·rust·开源项目·对象存储·minio·企业存储·rustfs
分布式存储与RustFS1 天前
MinIO替代方案生态集成指南:RustFS如何无缝融入现代技术栈
rust·github·开源项目·对象存储·minio·企业存储·rustfs
王燕龙(大卫)1 天前
rust:线程
开发语言·rust
李广坤1 天前
Rust基本使用
后端·rust
Source.Liu1 天前
【time-rs】Duration 结构体详解
rust·time
Chen--Xing1 天前
LeetCode 49.字母异位词分组
c++·python·算法·leetcode·rust
古城小栈1 天前
Go+Rust混合编程:高性能系统开发的最优解之一
golang·rust