以下代码运行不会是10,而是返回 0
Go
package main
import (
"fmt"
"github.com/spf13/cast"
)
type UserNum int32
func main() {
var uNum UserNum
uNum = 10
uNumint64 := cast.ToInt64(uNum)
uNumint64E, err := cast.ToInt64E(uNum)
fmt.Println(uNumint64)
fmt.Println(uNumint64E, err)
}
看一下源码,ToInt64()直接屏蔽了错误,可以使用 ToInt64E 这种,返回带错误的函数
Go
// ToInt64 casts an interface to an int64 type.
func ToInt64(i interface{}) int64 {
v, _ := ToInt64E(i)
return v
}
// ToInt64E casts an interface to an int64 type.
func ToInt64E(i interface{}) (int64, error) {
i = indirect(i)
intv, ok := toInt(i)
if ok {
return int64(intv), nil
}
switch s := i.(type) {
case int64:
return s, nil
case int32:
return int64(s), nil
case int16:
return int64(s), nil
case int8:
return int64(s), nil
case uint:
return int64(s), nil
case uint64:
return int64(s), nil
case uint32:
return int64(s), nil
case uint16:
return int64(s), nil
case uint8:
return int64(s), nil
case float64:
return int64(s), nil
case float32:
return int64(s), nil
case string:
v, err := strconv.ParseInt(trimZeroDecimal(s), 0, 0)
if err == nil {
return v, nil
}
return 0, fmt.Errorf("unable to cast %#v of type %T to int64", i, i)
case json.Number:
return ToInt64E(string(s))
case bool:
if s {
return 1, nil
}
return 0, nil
case nil:
return 0, nil
default:
return 0, fmt.Errorf("unable to cast %#v of type %T to int64", i, i)
}
}