springmvc：设置后端响应给前端的json数据转换成String格式

Uso_Magic2023-09-05 20:02

设置spring-mvc.xml:

'''xml

XML 复制代码

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:context="http://www.springframework.org/schema/context"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
       http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
">
    <!--将bean交给dispatcherServlet使用-->
    <context:component-scan base-package="com.ekgc.controller"/>
    <!--    设置后端响应给前端的json数据转换成String格式-->
    <bean id="stringConverter"
          class="org.springframework.http.converter.StringHttpMessageConverter">
        <property name="writeAcceptCharset" value="false" />
        <property name="supportedMediaTypes">
            <list>
                <value>text/html;charset=UTF-8</value>
            </list>
        </property>
    </bean>
    <bean id="jsonConverter" class="org.springframework.http.converter.json.MappingJackson2HttpMessageConverter"/>

    <bean class="org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerAdapter">
        <property name="messageConverters">
            <list>
                <ref bean="stringConverter" />
                <ref bean="jsonConverter" />
            </list>
        </property>
    </bean>
</beans>

'''

web.xml读取spring-mvc.xml

'''xml

XML 复制代码

<!DOCTYPE web-app PUBLIC
 "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
 "http://java.sun.com/dtd/web-app_2_3.dtd" >

<web-app>
  <context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>classpath:spring-config.xml</param-value>
  </context-param>

<!-- 监听spring容器 -->
  <listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
  </listener>

  <servlet>
    <servlet-name>springMVC</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
      <param-name>contextConfigLocation</param-name>
      <param-value>classpath:spring-mvc.xml</param-value>
    </init-param>
  </servlet>
  <servlet-mapping>
    <servlet-name>springMVC</servlet-name>
    <url-pattern>/</url-pattern>
  </servlet-mapping>
</web-app>

'''