socket.error: [Errno 10049]错误

woshicaiji121382023-10-06 23:20

今天在pycharm运行rl_server_no_training.py欲启动服务器时，却出现如下错误

powershell 复制代码

Traceback (most recent call last):
  File "xxx/rl_server_no_training.py", line 333, in <module>
    main()
  File "xxx/rl_server_no_training.py", line 326, in main
    run(log_file_path=LOG_FILE + '_RL_' + trace_file)
  File "xxx/rl_server_no_training.py", line 314, in run
    httpd = server_class(server_address, handler_class)
  File "xx\anaconda\envs\pensieve\lib\SocketServer.py", line 420, in __init__
    self.server_bind()
  File "xx\anaconda\envs\pensieve\lib\BaseHTTPServer.py", line 108, in server_bind
    SocketServer.TCPServer.server_bind(self)
  File "xx\anaconda\envs\pensieve\lib\SocketServer.py", line 434, in server_bind
    self.socket.bind(self.server_address)
  File "xx\anaconda\envs\pensieve\lib\socket.py", line 228, in meth
    return getattr(self._sock,name)(*args)
socket.error: [Errno 10049] 

Process finished with exit code 1

这种问题一般是监听的ip地址出现问题了。

上面代码我在本地PC运行，通过win+R，输入cmd，再输入ipconfig可查询本地ip地址。

对比，发现果然与server_address = ('xxx.xxx.xxx.xxx', port)中的ip地址不一样。

接下来将server_address = ('xxx.xxx.xxx.xxx', port)中的ip地址替换成刚刚查询到的本地ip地址。

没有报错，成功。