sql 查询 不满足 （一个教师编号 的角色 （role =‘2‘or（role=‘1‘and role =‘0‘）） ）

sql 查询 不满足 （一个教师编号 的角色 （role ='2'or（role='1'and role ='0'）） ）

准备 一个 teacher 表 和数据

表 teacher 和数据

-- ----------------------------
-- Table structure for teacher
-- ----------------------------
DROP TABLE IF EXISTS `teacher`;
CREATE TABLE `teacher`  (
  `id` int(11) NOT NULL AUTO_INCREMENT COMMENT 'id',
  `role` int(11) NULL DEFAULT NULL COMMENT '（角色;0：普通教师 1：班主任教师，2：普通教师 + 班主任）',
  `teacher_no` varchar(11) CHARACTER SET utf8 COLLATE utf8_general_ci NULL DEFAULT NULL COMMENT '教师编号',
  PRIMARY KEY (`id`) USING BTREE
) ENGINE = InnoDB AUTO_INCREMENT = 8 CHARACTER SET = utf8 COLLATE = utf8_general_ci ROW_FORMAT = Dynamic;

-- ----------------------------
-- Records of teacher
-- ----------------------------
INSERT INTO `teacher` VALUES (1, 0, 'T001');
INSERT INTO `teacher` VALUES (2, 1, 'T001');
INSERT INTO `teacher` VALUES (3, 2, 'T002');
INSERT INTO `teacher` VALUES (4, 0, 'T003');
INSERT INTO `teacher` VALUES (5, 1, 'T004');
INSERT INTO `teacher` VALUES (6, 0, 'T005');
INSERT INTO `teacher` VALUES (7, 1, 'T006');

SET FOREIGN_KEY_CHECKS = 1;

teacher 表 正确数据 截图

根据sql 查出来 不正确数据

sql

SELECT DISTINCT t1.teacher_no
FROM (
    SELECT teacher_no,
           MAX(CASE WHEN Role = '0' THEN 1 ELSE 0 END) AS role_ZERO_count,
           MAX(CASE WHEN Role = '1' THEN 1 ELSE 0 END) AS role_One_count,
           MAX(CASE WHEN Role = '2' THEN 1 ELSE 0 END) AS role_Two_flag
    FROM teacher
    GROUP BY teacher_no
) t2
JOIN teacher t1
ON t1.teacher_no = t2.teacher_no
WHERE NOT(t2.role_Two_flag = 1 OR (t2.role_ZERO_count = 1 AND t2.role_One_count = 1))

不正确数据 截图