常用的sql语句

一条sql语句更新两个表的内容的sql语句

UPDATE urlName,siteName SET url=@url,name=@name WHERE siteName.zid=urlName.zid AND ID=@IN ;

select * from user_tab_comments;//查询表的注释

select * from user_col_comments;//查询列的注释

select * from all_tables;//查询此用户下面所有的表

select * from dba_col_comments where column_name like '%LINECATE%'and (owner like 'JTVRAIL' OR owner like 'MAXRAIL');//查询dba下面的哪个column的名字带有LINECATE

1.create table users(

id number(20),

name varchar2(10)

);

2.select username from dba_users;//查看当前的所有用户

select * from dba_users; 查看数据库里面所有用户，前提是你是有dba权限的帐号，如sys,system

select * from all_users; 查看你能管理的所有用户！

select * from user_users; 查看当前用户信息！

4.select * from dba_sys_privs;

select * from user_sys_privs;

查看用户对象权限

select * from dba_tab_privs;

select * from all_tab_privs;

select * from user_tab_privs;

select s.grantee ,count(*) from dba_sys_privs s group by s.grantee;--查询用户下面有多少个权限

5查看用户系统权限

select * from dba_sys_privs;

select * from all_sys_privs;

select * from user_sys_privs;

select * from dba_roles;//查看所有角色

查看用户所拥有的角色

select * from dba_role_privs;

select * from user_role_privs;

select username,default_tablespace from user_users;//查看当前用户的缺省表空间

select extract(year from date'2011-05-17') year from dual;

SELECT * from mf_report_define WHERE report_name = 'workCount';

SELECT * from mf_report_define_item WHERE report_id='2c90db9e47f66223014815228c5d0030';

SELECT * FROM workorderappr_tg;

CREATE TABLE A(

ID NUMBER(2),

NAME VARCHAR2(3)

);

CREATE TABLE B(

ID NUMBER(2),

AID NUMBER(2),

NAME VARCHAR2(3)

);

INSERT into A values(3,'A3');

INSERT into B values(3,3,'B3');

SELECT * from A;

SELECT * from B WHERE B.AID = 1;

SELECT ID,NAME FROM A WHERE EXISTS (SELECT * FROM B WHERE A.ID=B.AID);

SELECT ID,NAME FROM A WHERE EXISTS(SELECT * FROM B WHERE B.AID = 1);

SELECT * from B FOR UPDATE;

F596EA0E65C747E3A53BE984F24E89A4

comment on TABLE plan_pro IS '工电问题录入管理' ;更改数据库表的注释

select * from user_col_comments WHERE comments LIKE '%车间%';

select * from user_col_comments WHERE column_name LIKE '%TUR%';

//获取table_name和collumn_name包含GEN的字段

select * from User_Tab_Columns WHERE column_name LIKE '%GEN%';//表的注释

SELECT * from USER_COL_COMMENTS;//字段的注释

SELECT ut.TABLE_NAME,ut.COLUMN_NAME,uc.comments

from User_Tab_Columns ut,USER_COL_COMMENTS uc

WHERE ut.column_name LIKE '%GEN%' AND ut.TABLE_NAME = uc.table_name

AND ut.COLUMN_NAME = uc.column_name;

select * from user_col_comments WHERE column_name LIKE '%DEPT%';

select * from user_constraints c where c.constraint_type = 'R' and c.table_name='STAFFPOSITION';

1.create table users(

id number(20),

name varchar2(10)

);

2.select username from dba_users;//查看当前的所有用户

select * from dba_users; 查看数据库里面所有用户，前提是你是有dba权限的帐号，如sys,system

select * from all_users; 查看你能管理的所有用户！

select * from user_users; 查看当前用户信息！

4.select * from dba_sys_privs;

select * from user_sys_privs;

查看用户对象权限

select * from dba_tab_privs;

select * from all_tab_privs;

select * from user_tab_privs;

5查看用户系统权限

select * from dba_sys_privs;

select * from all_sys_privs;

select * from user_sys_privs;

select * from dba_roles;//查看所有角色

查看用户所拥有的角色

select * from dba_role_privs;

select * from user_role_privs;

select username,default_tablespace from user_users;//查看当前用户的缺省表空间

select extract(year from date'2011-05-17') year from dual;

SELECT * from mf_report_define WHERE report_name = 'workCount';

SELECT * from mf_report_define_item WHERE report_id='2c90db9e47f66223014815228c5d0030';

SELECT * FROM workorderappr_tg;

CREATE TABLE A(

ID NUMBER(2),

NAME VARCHAR2(3)

);

CREATE TABLE B(

ID NUMBER(2),

AID NUMBER(2),

NAME VARCHAR2(3)

);

INSERT into A values(3,'A3');

INSERT into B values(3,3,'B3');

SELECT * from A;

SELECT * from B WHERE B.AID = 1;

SELECT ID,NAME FROM A WHERE EXISTS (SELECT * FROM B WHERE A.ID=B.AID);

SELECT ID,NAME FROM A WHERE EXISTS(SELECT * FROM B WHERE B.AID = 1);

SELECT * from B FOR UPDATE;

F596EA0E65C747E3A53BE984F24E89A4

--第一种方法: 查询dba_tab_columns

select COLUMN_NAME,DATA_TYPE,DATA_LENGTH

from dba_tab_columns

where table_name =upper('表名')

order by COLUMN_NAME

--这种方法需要有DBA权限

--第二种方法: 查询user_tab_cols

select COLUMN_NAME,DATA_TYPE,DATA_LENGTH

from user_tab_cols

where table_name=upper('表名')

order by COLUMN_NAME

--这种方法只能查找当前用户下的表

--第三种方法: 查询ALL_TAB_COLUMNS

select distinct COLUMN_NAME,DATA_TYPE,DATA_LENGTH

from ALL_TAB_COLUMNS

WHERE TABLE_NAME= upper('表名')

--这种方法可以查询所有用户下的表

---------------------------补充-------------------------------------------------------------

--增加字段

alter table cw_srcbpb

add (SRCBPB_RJBPBL varchar2(100) );

alter table cw_srcbpb

modify (SRCBPB_RJBPBL number(30,3) );

--Oracle查看所有表和字段

--获取表：

select table_name from user_tables; --当前用户的表

select table_name from all_tables; --所有用户的表

select table_name from dba_tables; --包括系统表

select table_name from dba_tables where owner='LBSP'; --获取用户***所拥有的表这里的用户名要记得是用大写的。

-- 获取表字段：其实这里是根据用户的权限来获取字段的属性（表名要大写）

select * from user_tab_columns where Table_Name='用户表';--获取用户表的所有字段还有字段的属性。

select * from all_tab_columns where Table_Name='用户表';--获取用户表的所有字段还有字段的属性。所属用户是***

select * from dba_tab_columns where Table_Name='用户表';--获取用户表的所有字段还有字段的属性。所属用户是***

--获取表注释：

select * from user_tab_comments

--user_tab_comments：table_name,table_type,comments

--相应的还有dba_tab_comments，all_tab_comments，这两个比user_tab_comments多了ower列。

--获取字段注释：

select * from user_col_comments--注意的是user_col_comments里面的column_name的字段的值在进行like的搜索的时候这个时候一定要大写

--user_col_comments：table_name,column_name,comments

--相应的还有dba_col_comments，all_col_comments，这两个比user_col_comments多了ower列。

--查询出用户所有表的索引

select * from user_indexes

--查询用户表的索引(非聚集索引):

select * from user_indexes where uniqueness='NONUNIQUE'

--查询用户表的主键(聚集索引):

select * from user_indexes where uniqueness='UNIQUE'

--查询表的索引

select t.*,i.index_type from user_ind_columns t,user_indexes i where t.index_name = i.index_name and

t.table_name='NODE'

--查询表的主键

select cu.* from user_cons_columns cu, user_constraints au where cu.constraint_name = au.constraint_name and

au.constraint_type = 'P' AND cu.table_name = 'NODE'

--查找表的唯一性约束（包括名称，构成列）：

select column_name from user_cons_columns cu, user_constraints au where cu.constraint_name=au.constraint_name and

cu.table_name='NODE'

--查找表的外键

select * from user_constraints c where c.constraint_type = 'R' and c.table_name='STAFFPOSITION'

--查询外键约束的列名：

select * from user_cons_columns cl where cl.constraint_name = 外键名称

--查询引用表的键的列名：

select * from user_cons_columns cl where cl.constraint_name = 外键引用表的键名

查询主键的值

select * from user_indexes where uniqueness= 'UNIQUE' AND index_name LIKE '%pk%' OR index_name LIKE '%PK%';

SELECT * from user_tab_cols;--这条sql语句能获取到表的所有的字段的值还有其类型等等

上面编辑页面

上面红线除外的是列表页面,红线是查询页面

SELECT * FROM dba_tables WHERE table_name LIKE '%ASSETDEPT%';

SELECT COLUMN_NAME FROM User_Tab_Columns@gdlink WHERE table_name='ASSET' AND DATA_TYPE='VARCHAR2';

dblink

tnsnames.ora

1.select * from TBSYS_PERMISSIONS where instr(smid, '2') > 0;//查询出TBSYS_PERMISSIONS的smid字段包含2的行数

select * from TBSYS_PERMISSIONS where smid like '%2%';//上面的instr属性类似于这句sql

首先想到的就是contains，contains用法如下：

|---|---------------------------------------------------------------------|
| 1 | select * from students where contains(address, 'beijing'``) |

但是，使用contains谓词有个条件，那就是列要建立索引，也就是说如果上面语句中students表的address列没有建立索引，那么就会报错。

DB2当前的时间减去一天的时间

SELECT SYSDATE - 1 DAY FROM DUAL

WITH WORKERS AS(

SELECT 'DOM1' DEPT, 'ZHANGSAN' NAMES , 23 AGE, 4000 SALARIES FROM DUAL UNION ALL

SELECT 'DOM1' DEPT, 'LISI' NAMES , 35 AGE, 9000 SALARIES FROM DUAL UNION ALL

SELECT 'DOM1' DEPT, 'ZHANGCHEN' NAMES, 35 AGE, 9000 SALARIES FROM DUAL UNION ALL

SELECT 'DOM1' DEPT, 'QIANSI' NAMES , 35 AGE, 4000 SALARIES FROM DUAL UNION ALL

SELECT 'DOM2' DEPT, 'WANGWU' NAMES , 26 AGE, 6500 SALARIES FROM DUAL UNION ALL

SELECT 'DOM2' DEPT, 'MALIU' NAMES , 28 AGE, 6000 SALARIES FROM DUAL UNION ALL

SELECT 'DOM2' DEPT, 'ZHAOQI' NAMES , 26 AGE, 5000 SALARIES FROM DUAL UNION ALL

SELECT 'DOM1' DEPT, 'LIBA' NAMES , 23 AGE, 3000 SALARIES FROM DUAL

)

SELECT S.NAMES,S.SALARIES,S.NAMES,DEPT, ROW_NUMBER() OVER(PARTITION BY DEPT ORDER BY SALARIES DESC)RANK FROM WORKERS S;

上面的PARTITION BY DEPT是以DEPT分组然后在这一组内进行排序,正如上面的DOM1分为1,2,3,4,5,下面的DOM2分为一组1,2,3

ROW_NUMBER()逐个增加一