java根据List＜Object＞中的某个属性排序(数据极少，顺序固定)

public static void main(String\[\] args) {

List<HashMap<String, Object>> dydj = new ArrayList<>();

// 模拟原始数据

HashMap<String, Object> map1 = new HashMap<>();

map1.put("city_name", "张家口");

map1.put("wjs", 0);

map1.put("yjs", 0);

map1.put("zxz", 0);

map1.put("wc", 0);

HashMap<String, Object> map2 = new HashMap<>();

map2.put("city_name", "唐山");

map2.put("wjs", 0);

map2.put("yjs", 0);

map2.put("zxz", 0);

map2.put("wc", 0);

dydj.add(map1);

dydj.add(map2);

        List<String> orderList = Arrays.asList("唐山", "张家口", "承德", "廊坊", "超高压");
        dydj.sort(Comparator.comparingInt(o -> {
            String city = (String) o.get("city_name");
            return orderList.indexOf(city);
        }));
        System.out.println(dydj);
    }