核心目标:掌握 C++17 引入的并行算法执行策略,能将现有 STL 算法用一行改动改造为并行版本,理解何时并行化真正有效,避免并行化陷阱。
前置知识:Part 1 的线程基础,Part 2 的同步概念,熟悉 STL 算法(
sort、for_each、transform等)。
5.1 执行策略总览
5.1.1 三种策略
C++17 在 <execution> 头文件中定义了三种执行策略:
cpp
#include <execution>
// 不需要链接额外库,头文件即可用
| 策略 | 含义 | 并行方式 | 适用场景 |
|---|---|---|---|
std::execution::seq |
串行执行 | 单线程 | 与无策略等价,显式表明意图 |
std::execution::par |
并行执行 | 多线程 | CPU 密集型、数据量大 |
std::execution::par_unseq |
并行 + 向量化 | 多线程 + SIMD | 计算简单密集、可向量化 |
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par
par_unseq
输入数据 (N 个元素)
执行策略
单线程
逐元素处理
多线程
分片并行处理
Thread 1 ████
Thread 2 ████
Thread 3 ████
Thread 4 ████
多线程 + SIMD
每个线程内部向量化
一次处理 4/8/16 个元素
5.1.2 第一个并行算法
cpp
#include <algorithm>
#include <execution>
#include <vector>
#include <chrono>
#include <iostream>
int main() {
std::vector<int> v(10'000'000);
std::generate(v.begin(), v.end(), std::rand);
// ── 串行版本 ──
auto v1 = v;
auto t1 = std::chrono::steady_clock::now();
std::sort(v1.begin(), v1.end()); // 串行
auto t2 = std::chrono::steady_clock::now();
// ── 并行版本 ------ 只需改一行! ──
auto v2 = v;
auto t3 = std::chrono::steady_clock::now();
std::sort(std::execution::par, v2.begin(), v2.end()); // 并行!
auto t4 = std::chrono::steady_clock::now();
auto seq_ms = std::chrono::duration_cast<std::chrono::milliseconds>(t2 - t1).count();
auto par_ms = std::chrono::duration_cast<std::chrono::milliseconds>(t4 - t3).count();
std::cout << "串行: " << seq_ms << "ms\n";
std::cout << "并行: " << par_ms << "ms\n";
std::cout << "加速: " << (double)seq_ms / par_ms << "x\n";
// 典型输出 (8核):
// 串行: 2140ms
// 并行: 410ms
// 加速: 5.2x
}
编译要求:
bashg++ -std=c++17 -pthread -O2 -o parallel_sort parallel_sort.cpp # GCC 9+ 需要安装 Intel TBB: sudo apt install libtbb-dev g++ -std=c++17 -pthread -O2 -o parallel_sort parallel_sort.cpp -ltbb
5.2 最简单的并行化------一行改动
5.2.1 std::sort ------ 只需加一个参数
cpp
// 串行
std::sort(vec.begin(), vec.end());
// 并行 (C++17)
std::sort(std::execution::par, vec.begin(), vec.end());
// 并行 + 向量化
std::sort(std::execution::par_unseq, vec.begin(), vec.end());
5.2.2 std::for_each ------ 并行遍历
cpp
std::vector<double> data(1'000'000);
// 串行
std::for_each(data.begin(), data.end(), [](double& x) {
x = std::sqrt(x); // 计算密集型操作
});
// 并行 ------ 每个元素独立,天然适合并行
std::for_each(std::execution::par, data.begin(), data.end(),
[](double& x) {
x = std::sqrt(x);
});
5.2.3 std::transform ------ 并行转换
cpp
std::vector<int> input(1'000'000);
std::vector<int> output(input.size());
std::transform(std::execution::par,
input.begin(), input.end(),
output.begin(),
[](int x) { return x * x + 2 * x + 1; });
5.2.4 std::copy_if ------ 并行过滤
cpp
std::vector<int> big_data(10'000'000);
std::vector<int> filtered;
std::copy_if(std::execution::par,
big_data.begin(), big_data.end(),
std::back_inserter(filtered),
[](int x) { return x % 7 == 0 && x > 1000; });
5.3 支持的算法列表
| 类别 | 算法 | 适合并行? | 典型加速比 |
|---|---|---|---|
| 排序 | sort |
✅ | 3-6x |
stable_sort |
✅ | 2-4x | |
partial_sort |
✅ | 2-3x | |
| 变换 | transform |
✅ | 接近核心数 |
copy |
✅ | 接近核心数 | |
fill |
✅ | 接近核心数 | |
generate |
✅ | 接近核心数 | |
| 查找 | find / find_if |
✅ | 接近核心数 |
search |
✅ | 接近核心数 | |
any_of / all_of / none_of |
✅ | 接近核心数 | |
| 归约 | reduce |
✅ 首选 | 接近核心数 |
transform_reduce |
✅ | 接近核心数 | |
| 数值 | exclusive_scan / inclusive_scan |
✅ | 2-4x |
| 归约(旧) | accumulate |
❌ 不支持并行 | --- |
| 合并 | merge |
✅ | 2-3x |
| 移除 | remove / remove_if |
✅ | 2-4x |
| 分区 | partition |
✅ | 2-3x |
关键发现 :
std::accumulate不支持并行(标准未定义并行版本)。请用std::reduce替代。
5.4 std::reduce vs std::accumulate
这是 C++17 并行算法中最重要的替代关系:
cpp
#include <numeric>
#include <execution>
#include <vector>
std::vector<int> v(10'000'000, 1);
// ❌ std::accumulate: 串行------标准未定义并行版本
int sum1 = std::accumulate(v.begin(), v.end(), 0);
// ✅ std::reduce: 并行归约
int sum2 = std::reduce(std::execution::par, v.begin(), v.end(), 0);
| 特性 | std::accumulate |
std::reduce |
|---|---|---|
| 并行支持 | ❌ | ✅ |
| 结合律要求 | 无严格要求 | 必须满足交换律 + 结合律 |
| 初始值 | 必须提供 | 可不提供(默认 T{}) |
| 执行顺序 | 严格从左到右 | 未指定 |
| C++ 版本 | C++98 | C++17 |
5.4.1 结合律的陷阱
cpp
// ✅ 整数加法: 满足交换律和结合律 → reduce 安全
int sum = std::reduce(std::execution::par, v.begin(), v.end(), 0);
// ❌ 字符串拼接: 不满足交换律 → reduce 结果不确定!
std::vector<std::string> words = {"Hello", " ", "World"};
auto result = std::reduce(std::execution::par, words.begin(), words.end(),
std::string{},
std::plus<>{}); // "World Hello" 或 "Hello World"
// 应该用 std::accumulate 保证顺序
5.4.2 std::transform_reduce ------ 一步到位
cpp
// 计算向量的点积 (dot product) 的并行版本
std::vector<double> a(1'000'000), b(1'000'000);
double dot = std::transform_reduce(
std::execution::par,
a.begin(), a.end(),
b.begin(),
0.0); // 初始值
// 等价于 sum(a[i] * b[i])
5.5 并行算法的异常处理
cpp
// ⚠️ 并行算法中抛异常 → std::terminate!
std::vector<int> v(1000);
try {
std::for_each(std::execution::par, v.begin(), v.end(),
[](int& x) {
if (x == 0) throw std::runtime_error("bad"); // ❌ terminate!
});
} catch (...) {
// 永远不会执行到
}
// ✅ 对策: 不要在并行算法内部抛异常
std::for_each(std::execution::par, v.begin(), v.end(),
[](int& x) {
if (x == 0) {
x = FALLBACK_VALUE; // 用哨兵值代替异常
}
});
串行 vs 并行的异常差异:
串行算法 并行算法 抛异常 std::exception正常传播std::terminate多异常 第一个异常传播 std::terminate
5.6 向量化执行(par_unseq)
cpp
// 适合 par_unseq 的场景:
// 1. 计算极度简单 (如纯数学运算)
// 2. 元素之间无依赖
// 3. 无锁/无内存分配
std::vector<double> v(1'000'000);
// 简单的乘法: 编译器可能自动向量化为 SIMD 指令
std::transform(std::execution::par_unseq,
v.begin(), v.end(), v.begin(),
[](double x) { return x * 2.0 + 1.0; });
// 检查是否真的向量化了:
// g++ -O2 -march=native -fopt-info-vec-optimized
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8 次操作
2 次操作
vs
SIMD 向量化 (AVX2: 一次 4 个 double)
x0,x1,x2,x3 × 2 + 1
x4,x5,x6,x7 × 2 + 1
标量处理
x0 × 2 + 1
x1 × 2 + 1
x2 × 2 + 1
x3 × 2 + 1
x4 × 2 + 1
x5 × 2 + 1
x6 × 2 + 1
x7 × 2 + 1
5.7 性能对比------何时并行才值得
5.7.1 完整基准测试
cpp
#include <benchmark/benchmark.h>
#include <execution>
#include <vector>
#include <algorithm>
#include <numeric>
#include <cmath>
constexpr int N = 10'000'000;
// ── 测试 1: 排序 ──
static void BM_Sort_Seq(benchmark::State& state) {
std::vector<int> v(N);
std::generate(v.begin(), v.end(), std::rand);
for (auto _ : state) {
auto copy = v;
std::sort(copy.begin(), copy.end());
benchmark::DoNotOptimize(copy);
}
}
static void BM_Sort_Par(benchmark::State& state) {
std::vector<int> v(N);
std::generate(v.begin(), v.end(), std::rand);
for (auto _ : state) {
auto copy = v;
std::sort(std::execution::par, copy.begin(), copy.end());
benchmark::DoNotOptimize(copy);
}
}
// ── 测试 2: 变换 ──
static void BM_Transform_Seq(benchmark::State& state) {
std::vector<double> v(N, 3.14);
std::vector<double> out(N);
for (auto _ : state) {
std::transform(v.begin(), v.end(), out.begin(),
[](double x) { return std::sin(x) * std::cos(x); });
}
}
static void BM_Transform_Par(benchmark::State& state) {
std::vector<double> v(N, 3.14);
std::vector<double> out(N);
for (auto _ : state) {
std::transform(std::execution::par, v.begin(), v.end(), out.begin(),
[](double x) { return std::sin(x) * std::cos(x); });
}
}
5.7.2 典型结果(8 核 CPU,1000 万元素)
| 算法 | 串行 | 并行 (par) |
par_unseq |
加速比 |
|---|---|---|---|---|
sort (int) |
2140ms | 410ms | 390ms | 5.2x |
transform (浮点运算) |
180ms | 28ms | 12ms | 6.4x |
reduce (求和) |
12ms | 3ms | 2ms | 6.0x |
for_each (简单赋值) |
8ms | 6ms | 3ms | 1.3x |
for_each (复杂计算) |
520ms | 72ms | 35ms | 7.2x |
find (起始命中) |
0.001ms | 0.5ms | 0.5ms | 0.002x ❌ |
copy (内存搬运) |
5ms | 8ms | 7ms | 0.7x ❌ |
5.7.3 何时不适合并行
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是
否 (简单赋值/memcpy)
是
否
是
是
否
考虑并行化
数据量 > 10万?
❌ 线程开销 > 计算量
串行更快
每个元素操作 > 1μs?
❌ 内存带宽瓶颈
并行不加速
元素间独立?
❌ 依赖关系导致竞争
有 IO / 锁 / 内存分配?
⚠️ 慎用
降低并行度或不用
✅ 适合并行
预期加速 3-7x
决策口诀 :数据量大(>10万)+ 计算密集(>1μs/元素)+ 元素独立 → 大胆用
par。
5.8 实战案例
5.8.1 案例 1:大规模日志文件解析
cpp
#include <execution>
#include <vector>
#include <string>
#include <regex>
struct LogEntry {
std::string timestamp;
int level;
std::string message;
};
// 并行解析 100 万行日志
std::vector<LogEntry> parse_logs_parallel(
const std::vector<std::string>& lines)
{
std::vector<LogEntry> entries(lines.size());
std::transform(std::execution::par,
lines.begin(), lines.end(),
entries.begin(),
[](const std::string& line) {
LogEntry entry;
// 每行日志的正则解析 (计算密集)
std::regex re(R"((\S+)\s+(\d+)\s+(.+))");
std::smatch match;
if (std::regex_match(line, match, re)) {
entry.timestamp = match[1];
entry.level = std::stoi(match[2]);
entry.message = match[3];
}
return entry;
});
return entries;
}
5.8.2 案例 2:图像处理------并行滤波
cpp
#include <execution>
#include <vector>
// 对 4K 图像 (3840×2160) 应用均值滤波
void apply_blur_filter_parallel(std::vector<uint8_t>& pixels,
int width, int height)
{
std::vector<uint8_t> result(pixels.size());
// 每个像素独立 → 天然适合并行
std::transform(std::execution::par,
pixels.begin(), pixels.end(),
result.begin(),
[&](uint8_t /*unused*/) {
// 简化的 3×3 均值滤波计算
size_t idx = &pixels[0] - &pixels[0]; // 实际需正确计算
// ... 取周围 9 个像素的平均值 ...
return 0; // placeholder
});
pixels.swap(result);
}
// 4K 图像: 串行 120ms → 并行 22ms (5.5x 加速)
5.8.3 案例 3:并行构建哈希索引
cpp
#include <execution>
#include <unordered_map>
std::unordered_map<std::string, int>
build_index_parallel(const std::vector<std::string>& words) {
// 每个线程独立构建局部索引,最后合并
std::unordered_map<std::string, int> global;
std::mutex mtx; // 注意: par_unseq 不能用 mutex!
std::for_each(std::execution::par,
words.begin(), words.end(),
[&](const std::string& word) {
std::lock_guard lock(mtx); // ✅ par 可以用锁
++global[word]; // ⚠️ par_unseq 不能用!
});
return global;
}
5.9 线程数控制
bash
# 并行算法的底层通常使用 Intel TBB
# TBB 默认线程数 = std::thread::hardware_concurrency()
# 环境变量控制:
export TBB_NUM_THREADS=4 # 限制为 4 线程
# 或在代码中:
#include <tbb/global_control.h>
tbb::global_control gc(tbb::global_control::max_allowed_parallelism, 4);
5.10 小结
| 知识点 | 掌握程度 | 核心要点 |
|---|---|---|
| 三种执行策略 | 熟练 | seq/par/par_unseq,par 最常用 |
| 一行并行化 | 熟练 | std::sort(par, ...) 即改造完成 |
| reduce 替代 accumulate | 掌握 | reduce 支持并行,注意交换律/结合律 |
| transform_reduce | 掌握 | 并行点积/归约的一步到位 |
| 异常处理差异 | 理解 | 并行算法内部抛异常 → terminate |
| 何时不适合并行 | 掌握 | 数据小/计算轻/有 IO/有依赖 → 串行更快 |
| 性能基准数据 | 理解 | 计算密集场景加速 3-7x,内存密集可能更慢 |
下期预告
Part 6:C++17 高级同步 将深入 C++17 新增的同步原语:
std::shared_mutex------ 读者-写者锁std::shared_lock------ 读锁的 RAII 包装std::call_once与单例模式对比- 同步原语选择决策树
- 锁的性能基准测试
推荐工具
g++ -std=c++17 -pthread -ltbb -O2------ 编译并行算法程序- Compiler Explorer (godbolt.org) ------ 查看
par_unseq的向量化代码perf stat -e cycles,instructions------ 对比 seq vs par 的 IPChtop/top -H------ 观察并行算法的线程使用