判断一个字符串是否为另一个字符串旋转之后的字符串 （arr1是arr2右旋得到）

问题：

1.判断函数传参时忘记给arr2加[]

2.把if放在for之外，导致判断不出，程序报错

void reverse_right(char* right, char* left)
{
	assert(left != NULL);
	assert(right != NULL);
	while (right > left)
	{
		char* temp = *right;
		*right = *left;
		*left = temp;
		left++;
		right--;
	}
}
void turn_right(char* arr, int k)
{
	assert(arr != NULL);
	int len = strlen(arr);
	assert(k >= 0);
	//1
	reverse_right(arr + len - 1, arr + len - k);
	//2
	reverse_right(arr + len - 1 - k, arr);
	//3
	reverse_right(arr + len - 1, arr);
}
int panduan_right(char arr1[], char arr2[])
{
	int len = strlen(arr1);
	int i = 0;
	for ( i = 0; i < len; i++)
	{
		turn_right(arr1, 1);
		if (strcmp(arr1, arr2) == 0)
		{
			return 1;
		}
	}
	return 0;
}
int main()
{
	char arr1[] = "cdeab";
	char arr2[] = "abcde";
	int ret = panduan_right(arr1, arr2);
	if (ret == 1)
	{
		printf("y\n");
	}
	else
	{
		printf("n\n");
	}
	return 0;
}