[运维Shell脚本小试牛刀(三)::(cd (dirname 0)； pwd)命令详解](https://blog.csdn.net/u014635374/article/details/132579373 "运维Shell脚本小试牛刀(三)::(cd (dirname 0)； pwd)命令详解")
一: if---else.....fi 条件判断演示
root@www shelldic# cat checkpass.sh
#!/bin/bash -
#==================================================================================================================
FILE: checkpass.sh
USAGE: ./checkpass.sh
DESCRIPTION:
OPTIONS: -------
REQUIREMENTS: ---------
BUGS: ------
NOTES: --------
AUTHOR: ---------YangGe (TOM) ,YangGe.freedom@icloud.com
ORGANIZATION:
CREATED: 2023-8-24 09:11:20
REVISION: --------
#====================================================================================================================
显示提示用户输入密码,然后从标准输入隐式地读取用户输入,并将读取的内容赋值给变量pass
read -sp "Enter a password: " pass
如果变量pass的值为laogao,则显示验证通过的信息,然后退出脚本的执行,退出状态码为0
if test "$pass" == "laogao"
then
echo -e "\nPasswrod verified"
exit 0
fi
#退出脚本执行,退出状态码为1
exit 1
二: if---else if----else---fi fi 多层嵌套，根据不同的分支做出不同的决策
root@www shelldic# cat multeCheckpass.sh
#!/bin/bash -
#==================================================================================================================
FILE: multeChckepass.sh
USAGE: ./multeCheckpass.sh
DESCRIPTION: 该实例主要是演示if ----else-----fi 根据条件的不同结果可以采取不同的行为
OPTIONS: -------
REQUIREMENTS: ---------
BUGS: ------
NOTES: --------
AUTHOR: ---------YangGe (TOM) ,YangGe.freedom@icloud.com
ORGANIZATION:
CREATED: 2023-8-29 09:11:20
REVISION: --------
#====================================================================================================================
read -sp "请输入登录密码: " pass
if "$pass" == "yangge"
then
echo -e "\n你已经通过验证...."
exit 0
else
if "$pass"=="yangyangge"
then
echo -e "\n你输入的信息为: ${pass}, 你用通过认证....."
else
echo "\n 你输入的密码为：$pass , 该密码错误,你将被拒绝再次访问....."
fi
fi
root@www shelldic# cat multeNestecheckcount.sh
#!/bin/bash -
#==================================================================================================================
FILE: multeNestecheckcount.sh
USAGE: ./multeNestechckcount.sh
DESCRIPTION: if----else---fi 多级嵌套
OPTIONS: -------
REQUIREMENTS: ---------
BUGS: ------
NOTES: --------
AUTHOR: ---------YangGe (TOM) ,YangGe.freedom@icloud.com
ORGANIZATION:
CREATED: 2023-8-24 09:11:20
REVISION: --------
#====================================================================================================================
声明一个变量
declare -i count
提示用户输入一个数值,然后把该变量存入count变量中
read -p "请输入一个数值: " count
if $count -eq 100
then
echo -e "\nyou enter data Count is 100"
else
if $count -gt 100
then
echo -e "\nyou enter data count greater than 100."
else
echo -e "\n you enter data count less than 100..."
fi
fi