例子
addAll()
java
@Test
public void CopyListTest(){
Student student = Student.builder().id(1).name("张三").age(23).classId(1).build();
Student student2 = Student.builder().id(2).name("李四").age(22).classId(1).build();
List<Student> students = new ArrayList<>();
students.add(student);
students.add(student2);
System.out.println("旧的list");
for (Student stu : students){
System.out.println(stu);
}
List<Student> list2 = new ArrayList<>();
list2.addAll(students);
list2.stream().forEach(t->t.setClassId(2));
System.out.println("新的list");
for (Student stu : list2){
System.out.println("班级id"+stu.getClassId());
}
System.out.println("旧的list");
for (Student stu : students){
System.out.println("班级id"+stu.getClassId());
}
}
旧的list的值被改变
直接用 newList = oldList 是引用传递,复制的是地址
改变oldList里的内容同样也会影响到newList
newList.addAll(oldList)是值传递
但 用allAll() 原来的值也被改变了
解决
使用深度复制
java
public static <T> List<T> deepCopy(List<T> sourceList) throws IOException, ClassNotFoundException{
ByteArrayOutputStream bo= new ByteArrayOutputStream();
ObjectOutputStream oos= new ObjectOutputStream(bo);
oos.writeObject(sourceList);
ByteArrayInputStream bi= new ByteArrayInputStream(bo.toByteArray());
ObjectInputStream ois=new ObjectInputStream(bi);
@SuppressWarnings("unchecked")
List<T> dest = (List<T>)ois.readObject();
return dest;
}
所复制的元素如果是对象,需要实现序列化。
如果所复制的元素是字符
java
List<String> newList=new ArrayList<String>(oldList);