数组对象，名字相同的对象进行合并

需求：数组对象，name字段相同的进行合并，并将每条数据中的num累加，金额为合并之后的num*price

原始数据tableData

复制代码

<el-table
	  :data="tableData"
	  style="width: 100%; margin-bottom: 20px"
	  border
	>
		<el-table-column prop="date" label="日期"></el-table-column>
		<el-table-column prop="num" label="数量"></el-table-column>
		<el-table-column prop="name" label="名称"></el-table-column>
		<el-table-column prop="price" label="单价"></el-table-column>
	</el-table>
	const tableData = reactive([
		{ date: '2023-10-13',num: 30,name: '零食',price: 20, },
		{ date: '2023-12-23',num: 15,name: '干果',price: 56 },
		{ date: '2023-5-16',num: 50,name: '零食',price: 20 },
		{ date: '2023-8-21',num: 22,name: '干果',price: 56 },
		{ date: '2023-8-21',num: 22,name: '货物',price: 26 },
		{ date: '2023-9-12',num: 10,name: '衣服',price: 26 },
	])

现在需要将数据合并为以下展示形式：日期进行合并为多个数据合并之前的日期区间

复制代码

<el-table
	  :data="newData"
	  style="width: 100%; margin-bottom: 20px"
	  border
	>
		<el-table-column prop="date" label="日期"></el-table-column>
		<el-table-column prop="num" label="数量"></el-table-column>
		<el-table-column prop="name" label="名称"></el-table-column>
		<el-table-column prop="amount" label="金额"></el-table-column>
	</el-table>

js处理逻辑：

复制代码

const newData = ref([])
	const getData = ()=>{
		let temp = {}
		let start_date = ''
		let end_date = ''
		for(var i=0;i<tableData.length;i++){
			let item = tableData[i]
			let {name,date,price,num} = item
			if(temp[name] == null){
				temp[name] = JSON.parse(JSON.stringify(item))
				temp[name]['amount'] = num * price
				start_date = date.replace(/-/g, '')
				end_date = date.replace(/-/g, '')
			}else{
				item = JSON.parse(JSON.stringify(item))
				temp[name]['num'] += num
				temp[name]['amount'] += num * price
				end_date = date.replace(/-/g, '')
			}
			let dateRage = [start_date,end_date]
			const newDateRange = dateRage.filter((item)=>item != '')
			newDateRange.sort((a,b)=>{
				return new Date(a) - new Date(b)
			})
			temp[name]['date'] = newDateRange[0] + '-' + newDateRange[newDateRange.length - 1]
		}
		let newArr = []
		Object.keys(temp).forEach(item=>{
			newArr.push(temp[item])
		})
		newData.value = newArr
		
	}

需要注意：temp $name$ = JSON.parse(JSON.stringify(item))需要使用深copy，要不会导致合并之后的数据值不对