react 实现路由拦截

Goat恶霸詹姆斯2024-02-19 13:42

简单介绍下项目背景，我这里做了一个demo，前端使用mock数据，然后实现简单的路由拦截，校验session是否包含用户作为已登录的依据，react-router-dom是v6。不像vue可以设置登录拦截beforeenter，react需要我们自己加。

javascript 复制代码

//router.js
import React, { lazy } from "react";
import { Navigate } from 'react-router-dom'

const Error = lazy(() => import("@/pages/Error/Error.jsx"))
const Index = lazy(() => import("@/pages/Index/Index.jsx"))
const Login = lazy(() => import("@/pages/Login/Login.jsx"))

export const routes = [
    {
        path: "/",
        element: <Navigate to="/index"/>
    },
    {
        path: "/login",
        element: <Login />
    },
    {
        path: "/index",
        element: <Index />
    },
    {
        path: "*",
        element: <Error />
    },
]

javascript 复制代码

import React, { useEffect, Suspense } from 'react'
import { useRoutes, useNavigate } from 'react-router-dom'
import { routes } from './router'

export default function Index() {
    const element = useRoutes(routes)

    return (
        <Authen route={element} children={element.children}>
            <Suspense>
                <div>{element}</div>
            </Suspense>
        </Authen>
    )

}
//实现路由拦截
const Authen = (props) => {
    const navigate = useNavigate()
    const { route, children } = props
    const username = sessionStorage.getItem('username')
    console.log(props);
    useEffect(() => {
        if (route.props.match.pathname === "/login" && username) {
            navigate('/index')
        }
    }, [route, navigate,username])
    return children
}

Surpense组件是react组件懒加载的时候，路由跳转了，由于网络原因，组件内容无法及时过去，不添加会报错。