leetcode - 1669. Merge In Between Linked Lists

Description

You are given two linked lists: list1 and list2 of sizes n and m respectively.

Remove list1's nodes from the ath node to the bth node, and put list2 in their place.

The blue edges and nodes in the following figure indicate the result:

Build the result list and return its head.

Example 1:

复制代码
Input: list1 = [10,1,13,6,9,5], a = 3, b = 4, list2 = [1000000,1000001,1000002]
Output: [10,1,13,1000000,1000001,1000002,5]
Explanation: We remove the nodes 3 and 4 and put the entire list2 in their place. The blue edges and nodes in the above figure indicate the result.

Example 2:

复制代码
Input: list1 = [0,1,2,3,4,5,6], a = 2, b = 5, list2 = [1000000,1000001,1000002,1000003,1000004]
Output: [0,1,1000000,1000001,1000002,1000003,1000004,6]
Explanation: The blue edges and nodes in the above figure indicate the result.

Constraints:

复制代码
3 <= list1.length <= 10^4
1 <= a <= b < list1.length - 1
1 <= list2.length <= 10^4

Solution

No other comments, just do simulation.

Time complexity: o ( n 1 + n 2 ) o(n1+n2) o(n1+n2)

Space complexity: o ( 1 ) o(1) o(1)

Code

python3 复制代码
# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, val=0, next=None):
#         self.val = val
#         self.next = next
class Solution:
    def mergeInBetween(self, list1: ListNode, a: int, b: int, list2: ListNode) -> ListNode:
        a_node, b_node = list1, list1
        b -= a - 1
        while a > 1:
            a_node = a_node.next
            a -= 1
        b_node = a_node.next
        while b > 0:
            b_node = b_node.next
            b -= 1
        a_node.next = list2
        list2_end = list2
        while list2_end.next:
            list2_end = list2_end.next
        list2_end.next = b_node
        return list1
相关推荐
纪元A梦9 分钟前
贪心算法应用:化工反应器调度问题详解
算法·贪心算法
深圳市快瞳科技有限公司40 分钟前
小场景大市场:猫狗识别算法在宠物智能设备中的应用
算法·计算机视觉·宠物
liulilittle1 小时前
OPENPPP2 —— IP标准校验和算法深度剖析:从原理到SSE2优化实现
网络·c++·网络协议·tcp/ip·算法·ip·通信
superlls3 小时前
(算法 哈希表)【LeetCode 349】两个数组的交集 思路笔记自留
java·数据结构·算法
田里的水稻4 小时前
C++_队列编码实例,从末端添加对象,同时把头部的对象剔除掉,中的队列长度为设置长度NUM_OBJ
java·c++·算法
纪元A梦4 小时前
贪心算法应用:保险理赔调度问题详解
算法·贪心算法
Jayden_Ruan5 小时前
C++逆向输出一个字符串(三)
开发语言·c++·算法
点云SLAM6 小时前
C++ 常见面试题汇总
java·开发语言·c++·算法·面试·内存管理
叙白冲冲6 小时前
哈希算法以及面试答法
算法·面试·哈希算法
YuTaoShao7 小时前
【LeetCode 每日一题】1277. 统计全为 1 的正方形子矩阵
算法·leetcode·矩阵