css 手写返回箭头

tengyuxin2024-04-11 18:32

因为在开发App时，为了自定义返回栏，返回箭头，一般都用图片，当图片不方便，最好用css样式实现。

逻辑：

画出一个正方形，让它旋转45度，只显示你需要的两个边即可

代码

html 复制代码

<!DOCTYPE html>
<html lang="en">

<head>
    <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
    <meta name="viewport"
        content="width=device-width,minimum-scale=1.0,maximum-scale=1.0,user-scalable=no,initial-scale=1">
    <meta name="format-detection" content="telephone=no">
    <meta name="apple-mobile-web-app-status-bar-style" content="white">
    <meta name="apple-mobile-web-app-capable" content="no">
    <title>Css arrow</title>
</head>
<style type="text/css">
    #triangle-facing-right {
        display: inline-block;
        margin: 72px;
        border-right: 24px solid;
        border-bottom: 24px solid;
        width: 120px;
        height: 120px;
        transform: rotate(-45deg);
    }

    #triangle-facing-left {
        display: inline-block;
        margin: 72px;
        border-left: 24px solid;
        border-bottom: 24px solid;
        width: 120px;
        height: 120px;
        transform: rotate(45deg);
    }
</style>

<body>
    <div id="triangle-facing-right"></div>
    <div id="triangle-facing-left"></div>
</body>



</html>