python 第一天 - 技术栈

循环打印

while循环

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languages = ["Regional Assembly Language","Autocode","FORTRAN","IPL (LISP的先驱)","FLOW-MATIC (COBOL的先驱)","COMTRAN (COBOL的先驱)","LISP","ALGOL 58","FACT (COBOL的先驱)","COBOL","APL","Simula","SNOBOL","CPL (C的先驱)","BASIC","PL/I","BCPL (C的先驱)","Logo","Pascal","Forth","C语言","Smalltalk","Prolog","ML","Scheme","SQL","Ada","C++","Common Lisp","MATLAB","Eiffel","Objective-C","Erlang","Perl","Tcl","FL (Backus)","Haskell","Python","Visual Basic","HTML","Ruby","Lua","CLOS (part of ANSI Common Lisp)","Java","Delphi (Object Pascal)","JavaScript","PHP","REBOL","D","C#","Visual Basic .NET","F#","Scala","Factor","Windows PowerShell","Rust","Clojure","Go"]
years = [1951, 1952, 1954, 1954, 1955, 1957, 1958, 1958, 1959, 1959, 1962, 1962, 1962, 1963, 1964, 1964, 1967 ,1968 ,1970 ,1970 ,1972 ,1972 ,1972 ,1973 ,1975 ,1978 ,1980 ,1983 ,1984 ,1984 ,1985 ,1986 ,1986 ,1987 ,1988 ,1989 ,1990 ,1991 ,1991 ,1991 ,1993 ,1993 ,1994 ,1995 ,1995 ,1995 ,1995 ,1997 ,1999 ,2001 ,2001 ,2002 ,2003 ,2003 ,2006 ,2006 ,2007 ,2009]
i = 0
while i < len(years):
    language = languages[i]
    year = years[i]
    print(language, ':', year)
    i += 1

for循环

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languages = ["Regional Assembly Language","Autocode","FORTRAN","IPL (LISP的先驱)","FLOW-MATIC (COBOL的先驱)","COMTRAN (COBOL的先驱)","LISP","ALGOL 58","FACT (COBOL的先驱)","COBOL","APL","Simula","SNOBOL","CPL (C的先驱)","BASIC","PL/I","BCPL (C的先驱)","Logo","Pascal","Forth","C语言","Smalltalk","Prolog","ML","Scheme","SQL","Ada","C++","Common Lisp","MATLAB","Eiffel","Objective-C","Erlang","Perl","Tcl","FL (Backus)","Haskell","Python","Visual Basic","HTML","Ruby","Lua","CLOS (part of ANSI Common Lisp)","Java","Delphi (Object Pascal)","JavaScript","PHP","REBOL","D","C#","Visual Basic .NET","F#","Scala","Factor","Windows PowerShell","Rust","Clojure","Go"]
years = [1951, 1952, 1954, 1954, 1955, 1957, 1958, 1958, 1959, 1959, 1962, 1962, 1962, 1963, 1964, 1964, 1967 ,1968 ,1970 ,1970 ,1972 ,1972 ,1972 ,1973 ,1975 ,1978 ,1980 ,1983 ,1984 ,1984 ,1985 ,1986 ,1986 ,1987 ,1988 ,1989 ,1990 ,1991 ,1991 ,1991 ,1993 ,1993 ,1994 ,1995 ,1995 ,1995 ,1995 ,1997 ,1999 ,2001 ,2001 ,2002 ,2003 ,2003 ,2006 ,2006 ,2007 ,2009]
i = 0
for i in range(0, len(languages)):
    language = languages[i]
    year = years[i]
    print(language, ':',year)
    i += 1

陌生语法：把for循环套在print函数里

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languages = ["Regional Assembly Language","Autocode","FORTRAN","IPL (LISP的先驱)","FLOW-MATIC (COBOL的先驱)","COMTRAN (COBOL的先驱)","LISP","ALGOL 58","FACT (COBOL的先驱)","COBOL","APL","Simula","SNOBOL","CPL (C的先驱)","BASIC","PL/I","BCPL (C的先驱)","Logo","Pascal","Forth","C语言","Smalltalk","Prolog","ML","Scheme","SQL","Ada","C++","Common Lisp","MATLAB","Eiffel","Objective-C","Erlang","Perl","Tcl","FL (Backus)","Haskell","Python","Visual Basic","HTML","Ruby","Lua","CLOS (part of ANSI Common Lisp)","Java","Delphi (Object Pascal)","JavaScript","PHP","REBOL","D","C#","Visual Basic .NET","F#","Scala","Factor","Windows PowerShell","Rust","Clojure","Go"]
years = [1951, 1952, 1954, 1954, 1955, 1957, 1958, 1958, 1959, 1959, 1962, 1962, 1962, 1963, 1964, 1964, 1967 ,1968 ,1970 ,1970 ,1972 ,1972 ,1972 ,1973 ,1975 ,1978 ,1980 ,1983 ,1984 ,1984 ,1985 ,1986 ,1986 ,1987 ,1988 ,1989 ,1990 ,1991 ,1991 ,1991 ,1993 ,1993 ,1994 ,1995 ,1995 ,1995 ,1995 ,1997 ,1999 ,2001 ,2001 ,2002 ,2003 ,2003 ,2006 ,2006 ,2007 ,2009]

[print(languages[i], ':', years[i]) for i in range(0, len(languages))]

问题:编写一个程序，它将找到所有这些数字，可被7整除，但不是5的倍数，2000年至3200年(包括在内)。得到的数字应按逗号分隔的顺序打印在一行上。

提示:考虑使用range(#begin， #end)方法

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l = []
for i in range(2000 , 3201):
    if (i%7==0) and (i%5!=0):
        l.append(str(i))
        
print(','.join(l))

join的使用：将容器之中的各个元素之间用指定符号连接。

问题:编写一个可以计算给定数的阶乘的程序。结果应该以逗号分隔的顺序打印在一行上。假设向程序提供以下输入:8

则输出为:40320

提示:在为问题提供输入数据的情况下，应该假设它是控制台输入。

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def fact(x):
    if x == 0:
        return 1
    return x * fact(x - 1)
x = int(input('请输入一个数字:'))
print(fact(x))

问题:使用给定的整数n，编写一个程序生成一个包含(i, i*i)的字典，该字典包含1到n之间的整数(两者都包含)。然后程序应该打印字典。

假设向程序提供以下输入:8

则输出为:

{1:1，2:4，3:9，4:16，5:25，6:36，,7:49，8:64}

提示:在为问题提供输入数据的情况下，应该假设它是控制台输入。考虑使用dict类型()