C语言 | Leetcode C语言题解之第143题重排链表

题目：

题解：

struct ListNode* middleNode(struct ListNode* head) {
    struct ListNode* slow = head;
    struct ListNode* fast = head;
    while (fast->next != NULL && fast->next->next != NULL) {
        slow = slow->next;
        fast = fast->next->next;
    }
    return slow;
}

struct ListNode* reverseList(struct ListNode* head) {
    struct ListNode* prev = NULL;
    struct ListNode* curr = head;
    while (curr != NULL) {
        struct ListNode* nextTemp = curr->next;
        curr->next = prev;
        prev = curr;
        curr = nextTemp;
    }
    return prev;
}

void mergeList(struct ListNode* l1, struct ListNode* l2) {
    struct ListNode* l1_tmp;
    struct ListNode* l2_tmp;
    while (l1 != NULL && l2 != NULL) {
        l1_tmp = l1->next;
        l2_tmp = l2->next;

        l1->next = l2;
        l1 = l1_tmp;

        l2->next = l1;
        l2 = l2_tmp;
    }
}

void reorderList(struct ListNode* head) {
    if (head == NULL) {
        return;
    }
    struct ListNode* mid = middleNode(head);
    struct ListNode* l1 = head;
    struct ListNode* l2 = mid->next;
    mid->next = NULL;
    l2 = reverseList(l2);
    mergeList(l1, l2);
}