[leetcode] n个骰子的点数

. - 力扣（LeetCode）

class Solution {
public:
    vector<double> statisticsProbability(int num) {
        vector<double> dp(6, 1.0 / 6.0);
        for (int i = 2; i <= num; i++) {
            vector<double> tmp(5 * i + 1, 0);
            for (int j = 0; j < dp.size(); j++) {
                for (int k = 0; k < 6; k++) {
                    tmp[j + k] += dp[j] / 6.0;
                }
            }
            dp = tmp;
        }
        return dp;
    }
};