华为机试HJ21简单密码

等风来随风飘2024-07-07 17:30

华为机试HJ21简单密码

题目：

现在有一种密码变换算法。九键手机键盘上的数字与字母的对应： 1--1， abc--2, def--3, ghi--4, jkl--5, mno--6, pqrs--7, tuv--8 wxyz--9, 0--0，把密码中出现的小写字母都变成九键键盘对应的数字，如：a 变成 2，x 变成 9.而密码中出现的大写字母则变成小写之后往后移一位，如：X ，先变成小写，再往后移一位，变成了 y ，例外：Z 往后移是 a 。数字和其它的符号都不做变换。数据范围：输入的字符串长度满足 1≤n≤100

想法：

根据上述规则找到对应的变换并输出

input_str = input()

l1 = ['a','b','c']
l2 = ['d','e','f']
l3 = ['g','h','i']
l4 = ['j','k','l']
l5 = ['m','n','o']
l6 = ['p','q','r','s']
l7 = ['t','u','v']
l8 = ['w','x','y','z']

result = ""

for i in input_str:
    if i in l1:
        result += "2"
    elif i in l2:
        result += "3"
    elif i in l3:
        result += "4"
    elif i in l4:
        result += "5"
    elif i in l5:
        result += "6"
    elif i in l6:
        result += "7"
    elif i in l7:
        result += "8"
    elif i in l8:
        result += "9"
    elif i < "Z" and i >= "A":
        result += chr(ord(i) + 32 + 1)
    elif i == "Z":
        result += "a"
    else:
        result += i

print(result)