代码随想录四刷day15

提示:文章写完后,目录可以自动生成,如何生成可参考右边的帮助文档

文章目录

  • 前言
  • [一、力扣100. 相同的树](#一、力扣100. 相同的树)
  • [二、力扣572. 另一棵树的子树](#二、力扣572. 另一棵树的子树)
  • [三、力扣104. 二叉树的最大深度](#三、力扣104. 二叉树的最大深度)
  • [四、力扣559. N 叉树的最大深度](#四、力扣559. N 叉树的最大深度)

前言


最小深度是从根节点到最近叶子节点的最短路径上的节点数量。

一、力扣100. 相同的树

递归

java 复制代码
/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
class Solution {
    public boolean isSameTree(TreeNode p, TreeNode q) {
        return fun(p,q);
    }
    public boolean fun(TreeNode p, TreeNode q){
        if(p == null && q == null){
            return true;
        }
        if(p == null || q == null){
            return false;
        }
        if(p.val != q.val){
            return false;
        }
        boolean b1 = fun(p.left, q.left);
        boolean b2 = fun(p.right,q.right);
        return b1 && b2;
    }
}

迭代

java 复制代码
/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
class Solution {
    public boolean isSameTree(TreeNode p, TreeNode q) {
        Deque<TreeNode> deq = new LinkedList<>();
        deq.offerLast(p);
        deq.offerLast(q);
        while(!deq.isEmpty()){
            TreeNode t1 = deq.pollFirst();
            TreeNode t2 = deq.pollFirst();
            if(t1 == null && t2 == null){
                continue;
            }
            if(t1 == null || t2 == null){
                return false;
            }
            if(t1.val != t2.val){
                return false;
            }
            deq.offerLast(t1.left);
            deq.offerLast(t2.left);
            deq.offerLast(t1.right);
            deq.offerLast(t2.right);
        }
        return true;
    }
}

二、力扣572. 另一棵树的子树

java 复制代码
/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
class Solution {
    public boolean isSubtree(TreeNode root, TreeNode subRoot) {
        return postOrder(root,subRoot);
    }
    public boolean postOrder(TreeNode root, TreeNode subRoot){
        if(root == null){
            return false;
        }
        boolean b1 = postOrder(root.left,subRoot);
        if(b1){
            return b1;
        }
        boolean b2 = postOrder(root.right,subRoot);
        if(b2){
            return b2;
        }
        boolean b3 = fun(root,subRoot);
        return b1 || b2 || b3;
    }
    public boolean fun(TreeNode p, TreeNode q){
        if(p == null && q == null){
            return true;
        }
        if(p == null || q == null){
            return false;
        }
        if(p.val != q.val){
            return false;
        }
        boolean b1 = fun(p.left,q.left);
        boolean b2 = fun(p.right,q.right);
        return b1 && b2;
    }
}

三、力扣104. 二叉树的最大深度

java 复制代码
/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
class Solution {
    public int maxDepth(TreeNode root) {
        return fun(root);
    }
    public int fun(TreeNode root){
        if(root == null){
            return 0;
        }
        int l = fun(root.left);
        int r = fun(root.right);
        return l > r ? l + 1 : r + 1;
    }
}

四、力扣559. N 叉树的最大深度

java 复制代码
/*
// Definition for a Node.
class Node {
    public int val;
    public List<Node> children;

    public Node() {}

    public Node(int _val) {
        val = _val;
    }

    public Node(int _val, List<Node> _children) {
        val = _val;
        children = _children;
    }
};
*/

class Solution {
    public int maxDepth(Node root) {
        return fun(root);
    }
    public int fun(Node root){
        if(root == null){
            return 0;
        }
        int max = 0;
        for(Node node : root.children){
            max = Math.max(max,fun(node));
        }
        return max + 1;
    }
}
相关推荐
wuweijianlove5 分钟前
算法设计中的空间复用与数据对齐优化的技术5
算法
qq_3331209723 分钟前
C++高并发内存池的整体设计和实现思路_C 语言
java·c语言·c++
mh_f26 分钟前
33.批量通过GET链接下载图片到指定文件夹下
java
金銀銅鐵28 分钟前
[Java] 如何理解 class 文件中方法的 access flags?
java·后端
智研数智工坊28 分钟前
SpringBoot4.0.6 + Security7.x + JWT 最新完整实战|无状态权限认证、统一异常处理、可直接落地
java·spring boot·spring security·jwt·权限认证
DIY源码阁31 分钟前
JavaSwing宿舍管理系统 - MySQL版
java·数据库·mysql·eclipse
Han_han91932 分钟前
递归相关题目:
java
yuan1999738 分钟前
基于 MATLAB PSO 工具箱的函数寻优算法
开发语言·算法·matlab
YUANQIANG202442 分钟前
博弈论中势函数与势博弈构造:为什么看似 “先射箭后画靶”
算法·信息与通信
kTR2hD1qb1 小时前
Claude Code Skill的介绍与使用
java·前端·数据库·人工智能