在js中拼接HTML页面报错

chi恩陈2024-08-28 21:30

在js中拼接HTML页面报错

// js拼接html时onclick，数字可以直接拼接，字符串必须加上引号

html 复制代码

οnclick=transferFilePage(1214324,'fihdsih8238');

// js拼接时html，变量需要引号隔开，否则在js中都会认为是字符串(" + opTypeStr + "),如果是放在onclick中则是('" + opTypeStr + "')，其中布尔类型(false)、数字(123)、onclick获取当前对象(this)、不是字符串的变量均不用加引号

html 复制代码

transferStr = "<td><div class='ui edit buttons thid'><button class='ui gray button mini' onclick=transferFilePage()>" + opTypeStr + "</button></div>" + overTime + "</td>";

//onclick函数中有多个参数：

html 复制代码

"<td>" +
      "<div class='ui edit buttons thid'>" +
       "<button class='ui gray button mini' οnclick='transferFilePage(" +
         	"'"+datas[i].report_id+"'," +
         	"'"+datas[i].temp_id+"'," +
            "'"+datas[i].userdeptid+"'," +
            "'"+datas[i].status+"'," +
            "'"+datas[i].fishId+"'," +
            "'"+datas[i].rectifyid+"'," +
            "'"+datas[i].transferid+"'," +
            "false," +  //布尔类型
            ""+hasRectifyPower+"," + //变量，不是字符串不用加引号（'fihdsih8238'）
            ""+hasTransferPower+"," +
            "'"+datas[i].adnumber.trim()+"'," +
            ""+opTypeStr+"," +
            ""+(datas[i].tempname ? datas[i].tempname.trim() : "")+"," +
             "this)'>" +
             opTypeStr +
        "</button>" +
    "</div>" +
    overTime +
"</td>";

// JSON字符串

html 复制代码

var jsonString = '{"name":"John", "age":30, "city":"New York"}';

// 使用JSON.parse()将其转换为JavaScript对象

html 复制代码

var obj = JSON.parse(jsonString);

//HTML中函数传递时注意需要对象转换成字符串

html 复制代码

JSON.stringify(obj).replace(/\"/g,"'");

// JSON对象

html 复制代码

var obj = {"name":"John", "age":30, "city":"New York"};
var jsonString = JSON.stringify(obj).replace(/\"/g,"'");