代码随想录训练营day51|图论part2

岛屿数量

卡码网题目链接

c 复制代码
#include <bits/stdc++.h>
using namespace std;

int dir[4][2] = {0,-1,0,1,1,0,-1,0};

void dfs(vector<vector<int>> &board, vector<vector<bool>> &visted, int x, int y){
    for(int i = 0; i < 4; i++){
        int nx = x + dir[i][0];
        int ny = y + dir[i][1];
        if(nx >= board.size() || nx < 0 || ny >= board[0].size() || ny < 0 || board[nx][ny] == 0 || visted[nx][ny])
            continue;
        // board[nx][ny] = 0;
        visted[nx][ny] = true;
        dfs(board, visted, nx, ny);
    }
}

void bfs(vector<vector<int>> &board, vector<vector<bool>> &visted, int x, int y){
    queue<pair<int, int>> que;
    que.push({x, y});
    while(!que.empty()){
        pair<int, int> s = que.front();
        que.pop();
        for(int i = 0; i < 4; i++){
            int nx = s.first + dir[i][0];
            int ny = s.second + dir[i][1];
            if(nx >= board.size() || nx < 0 || ny >= board[0].size() || ny < 0 || board[nx][ny] == 0 || visted[nx][ny])
                continue;
            visted[nx][ny] = true;
            que.push({nx, ny});
        }
    }

}

int main()
{
    int n, m;
    cin >> n >> m;
    vector<vector<int>> board(n, vector<int>(m));
    vector<vector<bool>> visted(n, vector<bool>(m, false));
    for(int i = 0; i < n; i++){
        for(int j = 0; j < m; j++){
            cin >> board[i][j];
        }
    }
    int result = 0;
    for(int i = 0; i < n; i++){
        for(int j = 0; j < m; j++){
            if(board[i][j] == 1 && !visted[i][j]){
                result++;
                visted[i][j] = true;
                // dfs(board, visted, i, j);
                bfs(board, visted, i, j);
            }
        }
    }
    cout << result << endl;
}

深搜

c 复制代码
int dir[4][2] = {0,-1,0,1,1,0,-1,0};
void dfs(vector<vector<int>> &board, vector<vector<bool>> &visted, int x, int y){
    for(int i = 0; i < 4; i++){
        int nx = x + dir[i][0];
        int ny = y + dir[i][1];
        if(nx >= board.size() || nx < 0 || ny >= board[0].size() || ny < 0 || board[nx][ny] == 0 || visted[nx][ny])
            continue;
        // board[nx][ny] = 0;
        visted[nx][ny] = true;
        dfs(board, visted, nx, ny);
    }
}

广搜

c 复制代码
int dir[4][2] = {0,-1,0,1,1,0,-1,0};
void bfs(vector<vector<int>> &board, vector<vector<bool>> &visted, int x, int y){
    queue<pair<int, int>> que;
    que.push({x, y});
    while(!que.empty()){
        pair<int, int> s = que.front();
        que.pop();
        for(int i = 0; i < 4; i++){
            int nx = s.first + dir[i][0];
            int ny = s.second + dir[i][1];
            if(nx >= board.size() || nx < 0 || ny >= board[0].size() || ny < 0 || board[nx][ny] == 0 || visted[nx][ny])
                continue;
            visted[nx][ny] = true;
            que.push({nx, ny});
        }
    }
}

岛屿的最大面积

卡码网题目链接(ACM模式)

c 复制代码
#include <bits/stdc++.h>
using namespace std;

int result;
int dir[4][2] = {0,-1,0,1,1,0,-1,0};
void bfs(vector<vector<int>> &board, vector<vector<bool>> &visted, int x, int y){
    queue<pair<int, int>> que;
    que.push({x, y});
    int sum = 1;
    while(!que.empty()){
        pair<int, int> s = que.front();
        que.pop();
        for(int i = 0; i < 4; i++){
            int nx = s.first + dir[i][0];
            int ny = s.second + dir[i][1];
            if(nx >= board.size() || nx < 0 || ny >= board[0].size() || ny < 0 || board[nx][ny] == 0 || visted[nx][ny])
                continue;
            sum++;
            visted[nx][ny] = true;
            que.push({nx, ny});
        }
    }
    result = max(sum, result);
}

int main()
{
    int n, m;
    cin >> n >> m;
    vector<vector<int>> board(n, vector<int>(m));
    vector<vector<bool>> visted(n, vector<bool>(m, false));
    for(int i = 0; i < n; i++){
        for(int j = 0; j < m; j++){
            cin >> board[i][j];
        }
    }
    result = 0;
    for(int i = 0; i < n; i++){
        for(int j = 0; j < m; j++){
            if(board[i][j] == 1 && !visted[i][j]){
                visted[i][j] = true;
                // result++;
                bfs(board, visted, i, j);
            }
        }
    }
    cout << result;
}
相关推荐
常某某的好奇心3 小时前
54. 二叉搜索树的第 k 大节点
算法
娇娇yyyyyy3 小时前
G1: Yunli‘s Subarray Queries (easy version)(1900)(定长区间众数)
算法
Lill_bin3 小时前
CAS机制:并发编程中的原子操作
java·服务器·开发语言·windows·算法·微服务
wh233z3 小时前
Codeforces Round 969 (Div. 2) (A~D)
c语言·开发语言·数据结构·c++·算法·图论
qq_550337994 小时前
研1日记12
人工智能·算法·机器学习
buaichifanqie5 小时前
拓扑排序算法
c++·算法·排序算法·图论·拓扑排序
MogulNemenis5 小时前
力扣100题——动态规划
算法·leetcode·动态规划
sjsjs115 小时前
【数据结构-一维差分】力扣1854. 人口最多的年份
数据结构·算法·leetcode
weixin_486681146 小时前
C++系列-谓词predicate
开发语言·c++·算法
理论最高的吻7 小时前
104. 二叉树的最大深度【 力扣(LeetCode) 】
数据结构·c++·算法·leetcode·职场和发展·二叉树