Write a solution to find all dates' id with higher temperatures compared to its previous dates (yesterday).
Return the result table in any order.
Input
Weather =
| id | recordDate | temperature |
|---|---|---|
| 1 | 2015-01-01 | 10 |
| 2 | 2015-01-02 | 25 |
| 3 | 2015-01-03 | 20 |
| 4 | 2015-01-04 | 30 |
Output
| id |
|---|
| 2 |
| 4 |
记住！！不可以写 w.recordDate = y.recordDate+ 1 因为是日期，跨月份会找不出来！
要写 DATEDIFF(w.recordDate, y.recordDate) = 1
My solution:
sql
SELECT w.id
FROM weather w
JOIN weather y
ON DATEDIFF(w.recordDate, y.recordDate) = 1
WHERE w.temperature > y.temperature