leetcode 100 热题 三数字之和

class Solution(object):

def twoSum(self, nums,target):

rt_list=[]

myDict={}

for i ,t in enumerate(nums):

myDict[t] = i

for i ,t in enumerate(nums):

if i>0 and nums[i-1]==nums[i]:

continue

if myDict.get(target-t)!=None and myDict.get(target-t)>i:

rt_list.append([t,target-t])

return rt_list

def threeSum(self, nums):

"""

:type nums: List[int]

:rtype: List[List[int]]

"""

rt_list=[]

nums.sort()

print(nums)

nums_tmp=nums.deepcopy()

for i ,t in enumerate(nums):

if i>0 and nums[i-1]==nums[i]:

continue

twosum_list = self.twoSum(nums[i+1:],0 - t)

print(twosum_list)

if len(twosum_list)>0:

for sub_list in twosum_list:

sub_list.append(t)

rt_list.append(sub_list)

rt_list2=[]

for i in rt_list:

i.sort()

rt_list2.append(i)

return rt_list2

一定要重视的是不能多次对同一个元素进行处理！！！一定要有continue部分和sort部分防止出现一样的结果