300.最长递增子序列
python
# Dynamic programming.
class Solution:
def lengthOfLIS(self, nums: List[int]) -> int:
if not nums: return 0
dp = [1] * len(nums)
for i in range(len(nums)):
for j in range(i):
if nums[j] < nums[i]: # 如果要求非严格递增,将此行 '<' 改为 '<=' 即可。
dp[i] = max(dp[i], dp[j] + 1)
return max(dp)
674. 最长连续递增序列
python
class Solution:
def findLengthOfLCIS(self, nums: List[int]) -> int:
l = 0 # 起点
r = 0 # 终点
maxLen = 0 # 待返回的最长长度
while r < len(nums):
if r == l or nums[r - 1] < nums[r]: # 保持递增
maxLen = max(maxLen, r - l + 1) # 比较取大
r += 1 # 终点前进
else: # 递增中断
l = r # 更新起点
return maxLen
718. 最长重复子数组
python
class Solution:
def findLength(self, A, B):
m, n = len(A), len(B)
ans = 0
dp = [[0 for _ in range(n + 1)] for _ in range(m + 1)]
for i in range(1, m + 1):
for j in range(1, n + 1):
if A[i - 1] == B[j - 1]:
dp[i][j] = dp[i - 1][j - 1] + 1
ans = max(ans, dp[i][j])
return ans