力扣-链表-19 删除链表倒数第N个节点

思路

链表题目中操作链表的需要找到要操作节点的上一个节点，所以cur是当前想要操作的节点上一个节点

代码

class Solution {
public:
    ListNode* removeNthFromEnd(ListNode* head, int n) {
        ListNode* dummy_head = new ListNode();
        dummy_head->next = head;
        int size = 0;
        while(head != nullptr){
            head = head->next;
            size++;
        }
        ListNode* cur = dummy_head;
        while(size - n){
            cur = cur->next;
            n++;
        }
        cur->next = cur->next->next;
        return dummy_head->next;
    }
};