Leetcode - 反转字符串

反转字符串

编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 s 的形式给出。

不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。

示例 1：

输入：s = "h","e","l","l","o"

输出："o","l","l","e","h"

示例 2：

输入：s = "H","a","n","n","a","h"

输出："h","a","n","n","a","H"

提示：

• 1 <= s.length <= 105
• si 都是 ASCII 码表中的可打印字符

解答：

public static void reverseString(char[] s) {
    int left = 0;
    int right = s.length - 1;
    while (left < right) {
        // 交换左右指针的字符
        char temp = s[left];
        s[left] = s[right];
        s[right] = temp;
        // 移动指针
        left++;
        right--;
    }
}