TypeScript ＞ 牛客OJ在线编程常见输入输出练习场

文章目录

• 牛客OJ在线编程常见输入输出练习场
• [A A+B(1)](#A A+B(1))
• [B A+B(2)](#B A+B(2))
• [C A+B(3)](#C A+B(3))
• [D A+B(4)](#D A+B(4))
• [E A+B(5)](#E A+B(5))
• [F A+B(6)](#F A+B(6))
• [G A+B(7)](#G A+B(7))
• [H 字符串排序(1)](#H 字符串排序(1))
• [I 字符串排序(2)](#I 字符串排序(2))
• [J 字符串排序(3)](#J 字符串排序(3))
• TypeScript输入输出要点总结

牛客OJ在线编程常见输入输出练习场

https://ac.nowcoder.com/acm/contest/5647

A A+B(1)

import * as readline from 'readline';

const rl = readline.createInterface({
    input: process.stdin,
    output: process.stdout
});

rl.on('line', (line) => {
    const nums = line.split(' ').map(Number);
    console.log(nums[0] + nums[1]);
});

B A+B(2)

import * as readline from 'readline';

const rl = readline.createInterface({
    input: process.stdin,
    output: process.stdout
});

const lines: string[] = [];
rl.on('line', (line) => {
    lines.push(line);
}).on('close', () => {
    const t = parseInt(lines[0]);
    for (let i = 1; i <= t; i++) {
        const nums = lines[i].split(' ').map(Number);
        console.log(nums[0] + nums[1]);
    }
});

C A+B(3)

import * as readline from 'readline';

const rl = readline.createInterface({
    input: process.stdin,
    output: process.stdout
});

rl.on('line', (line) => {
    const nums = line.split(' ').map(Number);
    if (nums[0] === 0 && nums[1] === 0) {
        rl.close();
        return;
    }
    console.log(nums[0] + nums[1]);
});

D A+B(4)

import * as readline from 'readline';

const rl = readline.createInterface({
    input: process.stdin,
    output: process.stdout
});

rl.on('line', (line) => {
    const nums = line.split(' ').map(Number);
    if (nums[0] === 0) {
        rl.close();
        return;
    }
    const sum = nums.slice(1).reduce((a, b) => a + b, 0);
    console.log(sum);
});

E A+B(5)

import * as readline from 'readline';

const rl = readline.createInterface({
    input: process.stdin,
    output: process.stdout
});

const lines: string[] = [];
rl.on('line', (line) => {
    lines.push(line);
}).on('close', () => {
    const t = parseInt(lines[0]);
    for (let i = 1; i <= t; i++) {
        const nums = lines[i].split(' ').map(Number);
        const sum = nums.slice(1).reduce((a, b) => a + b, 0);
        console.log(sum);
    }
});

F A+B(6)

import * as readline from 'readline';

const rl = readline.createInterface({
    input: process.stdin,
    output: process.stdout
});

rl.on('line', (line) => {
    const nums = line.split(' ').map(Number);
    const sum = nums.slice(1).reduce((a, b) => a + b, 0);
    console.log(sum);
});

G A+B(7)

import * as readline from 'readline';

const rl = readline.createInterface({
    input: process.stdin,
    output: process.stdout
});

rl.on('line', (line) => {
    const sum = line.split(' ').map(Number).reduce((a, b) => a + b, 0);
    console.log(sum);
});

H 字符串排序(1)

import * as readline from 'readline';

const rl = readline.createInterface({
    input: process.stdin,
    output: process.stdout
});

const lines: string[] = [];
rl.on('line', (line) => {
    lines.push(line);
}).on('close', () => {
    const strs = lines[1].split(' ');
    strs.sort();
    console.log(strs.join(' '));
});

I 字符串排序(2)

import * as readline from 'readline';

const rl = readline.createInterface({
    input: process.stdin,
    output: process.stdout
});

rl.on('line', (line) => {
    const strs = line.split(' ');
    strs.sort();
    console.log(strs.join(' '));
});

J 字符串排序(3)

链接：https://ac.nowcoder.com/acm/contest/5647/J

输入描述:

多个测试用例，每个测试用例一行。

每行通过,隔开，有n个字符，n＜100

输出描述:

对于每组用例输出一行排序后的字符串，用','隔开，无结尾空格

import * as readline from 'readline';

const rl = readline.createInterface({
    input: process.stdin,
    output: process.stdout
});

rl.on('line', (line) => {
    const strs = line.trim().split(',');
    strs.sort();
    console.log(strs.join(','));
});

TypeScript输入输出要点总结

场景	写法
引入readline模块	import * as readline from 'readline';
创建接口	const rl = readline.createInterface({input: process.stdin, output: process.stdout});
逐行读取	rl.on('line', (line) => {...})
读取完成回调	rl.on('close', () => {...})
按空格分割	line.split(' ')
转换为整数数组	.map(Number)
求和	nums.reduce((a, b) => a + b, 0)
字符串排序	strs.sort()
用分隔符连接	strs.join(' ')