python第三次作业

李松桃2026-01-29 12:19

题目为：

课堂练习，完成学生信息录入系统，直接存储在文件中，存储方式如下

#读取文件并对其学号排序并打印

"""

name: "张三",age:20,student_number:371897281,score_total=495

name: "三",age:20,student_number:371897281,score_total=495

name: "三",age:20,student_number:371897281,score_total=495

name: "三",age:20,student_number:371897281,score_total=495

"""

python 复制代码

#导入序列化模块
import pickle
list2 = [] #创建一个列表
#循环输入，可自行决定输入多少数据
while True:
    running = int(input("请选择操作：1、输入学生信息；2、退出操作："))
    if running == 1:
        name = input("请输入姓名name:")
        age = int(input("请输入年龄age:"))
        student_number = int(input("请输入student_number:"))
        score_total = int(input("请输入score_total:"))
        student = {}   #创建一个字典 因为k:v对形式存储的数据
        student["mame"] = name
        student["age"] = age
        student["student_number"] = student_number
        student["score_total"] =score_total
        
        list2.append(student)  #append()在其list2中末尾添加student的元素
    else :
        break
    res = pickle.dumps(list2) #序列化 dumps 
    with open("05python-io\list2.txt","wb") as l1:    
        l1.write(res)

with open("05python-io\list2.txt","rb") as l2:   
    res2 = l2.read()
list2_res = pickle.loads(res2) #反序列 loads

print("排序前录入的顺序：",list2)
list2.sort(key = lambda x:x["student_number"])
print("排序后录入的顺序：",list2)

运行结果：