JacksonUtilTest

public class JacksonUtilTest { public static void main(String[] args) { // 你的原始 JSON 字符串 String jsonStr = "{" + " \"clsAttrs\": [" + " {" + " \"productionCatlogLevel\": {" + " \"name\": \"3333333\"," + " \"brandInternationalName\": \"2222\"," + " \"states\": {" + " \"code\": \"停用\"," + " \"cnName\": \"停用\"" + " }" + " }" + " }" + " ]" + "}"; // 示例1：解析 JsonNode 并获取 name（你的核心需求） JsonNode jsonNode = JacksonUtil.toJsonNode(jsonStr); String name = JacksonUtil.getStringValue(jsonNode, "clsAttrs[0].productionCatlogLevel.name"); System.out.println("获取的name值：" + name); // 输出：3333333 // 示例2：获取嵌套的 states.cnName String cnName = JacksonUtil.getStringValue(jsonNode, "clsAttrs[0].productionCatlogLevel.states.cnName"); System.out.println("获取的cnName值：" + cnName); // 输出：停用 // 示例3：对象转 JSON（格式化输出） User user = new User("张三", 25); String userJson = JacksonUtil.toJson(user, true); System.out.println("对象转JSON：\n" + userJson); // 示例4：JSON 转复杂类型（List<Map>） String listJson = "[{\"name\":\"李四\",\"age\":30},{\"name\":\"王五\",\"age\":35}]"; List<Map<String, Object>> list = JacksonUtil.fromJson(listJson, new TypeReference<List<Map<String, Object>>>() {}); System.out.println("JSON转List：" + list); } // 测试用实体类 static class User { private String name; private Integer age; public User(String name, Integer age) { this.name = name; this.age = age; } // 省略 getter/setter（Jackson 序列化需要） public String getName() { return name; } public void setName(String name) { this.name = name; } public Integer getAge() { return age; } public void setAge(Integer age) { this.age = age; } } }