【day57】

给定两个仅由大写字母或小写字母组成的字符串(长度介于1到10之间)，它们之间的关系是以下4种情况之一：

1：两个字符串长度不等。比如 Beijing 和 Hebei

2：两个字符串不仅长度相等，而且相应位置上的字符完全一致(区分大小写)，比如 Beijing 和 Beijing

3：两个字符串长度相等，相应位置上的字符仅在不区分大小写的前提下才能达到完全一致（也就是说，它并不满足情况2）。比如 beijing 和 BEIjing

4：两个字符串长度相等，但是即使是不区分大小写也不能使这两个字符串一致。比如 Beijing 和 Nanjing

编程判断输入的两个字符串之间的关系属于这四类中的哪一类，给出所属的类的编号。

#include<iostream>
using namespace std;
int main() {
	string a, b;
	cin >> a >> b;
	int lena = a.size();
	int lenb = b.size();
	int cur = 2;
	if (lena != lenb) {
		cout << 1 << endl;
		return 0;
	}
	int gap = 'a' - 'A';
	for (int i = 0; i < lena; i++) {
		if (a[i] == b[i])continue;
		if (a[i] == b[i] + gap || a[i] + gap == b[i]) {
			cur = 3;
		}
		else {
			cur = 4;
			break;
		}
	}
	cout << cur << endl;
	return 0;
}

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