【JavaScript】华为机试_HJ20_密码验证合格程序

题目描述

你需要书写一个程序验证给定的密码是否合格。

合格的密码要求：

（1）长度不少于8位

（2）必须包含大写字母、小写字母、数字、特殊字符中的至少三种

（3）不能分割出两个独立的、长度大于2的连续子串，使得这两个子串完全相同

题目链接:https://www.nowcoder.com/practice/184edec193864f0985ad2684fbc86841?tpId=37\&tqId=21243\&rp=1\&sourceUrl=%2Fexam%2Foj%2Fta%3FtpId%3D37\&difficulty=undefined\&judgeStatus=undefined\&tags=\&title=

解答

第一次通过示例

javascript 复制代码

const rl = require("readline").createInterface({ input: process.stdin });
var iter = rl[Symbol.asyncIterator]();
const readline = async () => (await iter.next()).value;

void async function () {
    // Write your code here
    while(line = await readline()){
        let res = "OK";
        let count = 0;
        if (line.length < 8) {
            console.log("NG");
            continue;
        }
        count = line.match(/[A-Z]/) ? ++count : count;
        count = line.match(/[a-z]/) ? ++count : count;
        count = line.match(/[0-9]/) ? ++count : count;
        count = line.match(/[\x21-\x2F\x3A-\x40\x5B-\x60\x7B-\x7E]/) ? ++count : count;
        if (count < 3) {
            console.log("NG");
            continue;
        }
        for (let i = 0; i < line.length - 5; i++) {
            let substr = line.slice(i, i+3);
            if (i > 0 && line.slice(0, i).includes(substr)) {
                res = "NG";
                break;
            } else if (i+3 < line.length && line.slice(i+3).includes(substr)) {
                res = "NG";
                break;
            }
        }
        console.log(res);
    }
}()

优化

javascript 复制代码

const rl = require("readline").createInterface({ input: process.stdin });
var iter = rl[Symbol.asyncIterator]();
const readline = async () => (await iter.next()).value;

void async function () {
    // Write your code here
    while(line = await readline()){
        if (isPassword(line)) {
            console.log("OK");
        } else {
            console.log("NG");
        }
    }
}()

function isPassword (pwd) {
    if (!pwd || pwd.length < 8) return false;

    let matchCount = 0;
    const regs = [/\d/g, /[A-Z]/g, /[a-z]/g, /\W/g];
    regs.forEach( reg => matchCount = reg.test(pwd) ? ++matchCount : matchCount);
    if (matchCount < 3) return false;
    
    for (let i = 0; i < pwd.length - 5; i++) {
        const substr = pwd.slice(i, i+3);
        if (pwd.slice(i+3).includes(substr)) return false;
    }
    return true;
}