time limit per test
2 seconds
memory limit per test
256 megabytes
We call a positive integer number fair if it is divisible by each of its nonzero digits. For example, 102 is fair (because it is divisible by 1 and 2), but 282 is not, because it isn't divisible by 8. Given a positive integer n. Find the minimum integer x, such that n≤x and x is fair.
Input
The first line contains number of test cases t (1≤t≤103). Each of the next t lines contains an integer n (1≤n≤1018).
Output
For each of t test cases print a single integer --- the least fair number, which is not less than n.
Example
Input
Copy
4
1
282
1234567890
1000000000000000000
Output
Copy
1
288
1234568040
1000000000000000000
Note
Explanations for some test cases:
- In the first test case number 1 is fair itself.
- In the second test case number 288 is fair (it's divisible by both 2 and 8). None of the numbers from 282,287 is fair, because, for example, none of them is divisible by 8.
解题说明:此题是一道数学题,直接从 n开始逐个递增检查,直到找到第一个满足条件的数即可。针对每个数字,判断其中的每一位,如果为0就跳过,否则进行整除判断。
cpp
#include<stdio.h>
int main()
{
int t;
long long int a, k;
scanf("%d", &t);
while (t)
{
scanf("%lld", &a);
k = a;
while (k != 0)
{
if (k % 10 == 0)
{
k = k / 10;
}
else
{
if (a % (k % 10) == 0)
{
k = k / 10;
}
else
{
a++;
k = a;
}
}
}
printf("%lld\n", a);
t--;
}
return 0;
}