Use VC++2010 to open the solution in the examinee folder under prog1. The project of this solution contains a source file named prog1.c. In this program, the function fun() combines two positive integers a and b into one new integer stored in variable c.
Combination rules: The tens digit and units digit of a are placed to the tens position and thousands position of c in sequence. The tens digit and units digit of b are placed to the units position and hundreds position of c in sequence.
For example: when a=45, b=12, after calling this function, c=5241.
Note: Part of the source code is stored in prog1.c. Do not modify any content in main() or other existing functions. Only write several statements inside the braces of function fun().
Source code snippet:
#include <stdio.h>
void fun(int a, int b, long *c)
{
}
main()
{
int a,b; long c;void NONO();
printf("Input a, b:");
scanf("%d%d", &a, &b);
fun(a, b, &c);
printf("The result is: %ld\n", c);
NONO();
}
Key Test Points (English)
- Digit extraction of integer. Use division / and modulus % operator to get single digit of an integer.
- Pointer parameter. Use long *c to return calculation result to main function. Modify the value of outer variable inside function by pointer.
- Digit combination. Assemble separate digits into a new long integer with multiplication and addition.
- Function scope constraint. Only add code inside fun(), keep main and NONO function unchanged.
- Long data type. Use long type to avoid integer overflow for combined four‑digit number.
Brief Explanation
- a=45: units digit is 5, tens digit is 4.
- b=12: units digit is 2, tens digit is 1.
- According to rules: thousands =5, hundreds=1, tens=4, units=2 → final number 5241.
- We take digits by
a%10for units digit,a/10for tens digit. - Use pointer
*cto assign the final assembled number.
Reference complete fun function code
void fun(int a, int b, long *c)
{
int a1,a2,b1,b2;
a1 = a%10;
a2 = a/10;
b1 = b%10;
b2 = b/10;
*c = a1*1000 + b2*100 + a2*10 + b1;
}
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