给你一个整数数组 nums
,判断是否存在三元组 [nums[i], nums[j], nums[k]]
满足 i != j
、i != k
且 j != k
,同时还满足 nums[i] + nums[j] + nums[k] == 0
。请
你返回所有和为 0
且不重复的三元组。
**注意:**答案中不可以包含重复的三元组
class Solution {
public List<List<Integer>> threeSum(int[] nums) {
List<List<Integer>> millionYuanList = new ArrayList<>();
//人都不够仨,还三胎。。。
if(nums.length < 3) {
return millionYuanList;
}
Arrays.sort(nums); //孩子们按个头排好队
for(int i = 0; i < nums.length; i++) {
//如果老大都大于0,后面的兄弟肯定都大于0,直接返回就行
if(nums[i] > 0) break;
Integer first = nums[i]; //老大出列,站好别动
//老大想再往后占个位,多领一次奖,这可是不行滴。。。还是回家让妈妈再给生三个小弟弟吧^_^
if(i > 0 && nums[i] == nums[i - 1]) continue;
//画个圈,让各家老二在里面呆着
Set<Integer> set = new HashSet<>();
for(int j = i + 1; j < nums.length; j++) {
//老三出列,一会你和老大一块到圈里找老二
int third = nums[j];
int second = -(first + third); //目标是:老大 + 老二 + 老三 = 0
//找到老二了,记到中奖名单上
if(set.contains(second)) {
millionYuanList.add(new ArrayList<>(Arrays.asList(first, third, -(first + third))));
//老三也想多领奖。。。额。。。等会一块回家找妈妈去吧
while(j < nums.length - 1 && nums[j] == nums[j + 1]) j++;
}
set.add(third);
}
}
return millionYuanList;
}
}
三层循环
public class Solution {
public static void main(String[] args) {
int[] nums = new int[]{-4, -2, 1, -5, -4, -4, 4, -2, 0, 4, 0, -2, 3, 1, -5, 0};
System.out.println(threeSum(nums));
}
public static List<List<Integer>> threeSum(int[] nums) {
List<List<Integer>> threes = new ArrayList<>();
for (int i = 0; i < nums.length; i++) {
for (int j = i + 1; j < nums.length; j++) {
for (int k = j + 1; k < nums.length; k++) {
if (i == j || j == k || i == k) {
continue;
}
if (nums[i] + nums[j] + nums[k] == 0) {
List<Integer> three = new ArrayList<>();
three.add(nums[i]);
three.add(nums[j]);
three.add(nums[k]);
if (!contain(three, threes)) {
threes.add(three);
}
}
}
}
}
return threes;
}
public static boolean contain(List<Integer> three, List<List<Integer>> threes) {
for (List<Integer> list : threes) {
if (three.contains(list.get(0)) && three.contains(list.get(1)) && three.contains(list.get(2))
&& list.contains(three.get(0)) && list.contains(three.get(1)) && list.contains(three.get(2))) {
return true;
}
}
return false;
}
}