正则表达式替换占位符

解析占位符

如何从下面的一个字符串中解析除占位符，并根据变量的类型替换。

"(<{AMT_field_value,string}> == nil ? false : string.contains( <{AMT_rule_value,string}>, <{AMT_field_value,array}>))

代码如下

import org.apache.flink.api.java.tuple.Tuple2;

import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

/**
 * @className: ExpressionParser
 * @Description:
 * @Author: wangyifei
 * @Date: 2023/10/11 21:45
 */
public class ExpressionParser {
    public static void main(String[] args) {
        String str = "(<{AMT_field_value,string}> == nil ? false : string.contains( <{AMT_rule_value,string}>, <{AMT_field_value,array}>))";
        Pattern p = Pattern.compile("<\\{(.*?)\\}>");
        Matcher matcher = p.matcher(str);
        String find = "";
        String[] split = null ;
        String key = null;
        String value = null ;
        String replace = str ;
        Map<String,Object> parameter = new HashMap<>();
        parameter.put("AMT_field_value","vvvv");
        while (matcher.find()) {
            find = matcher.group(1);
            split = find.split("\\s*,\\s*");
            key = split[0];
            value = split[1];
            replace = replace.replace("<{"+find+"}>" , String.valueOf(parameter.get(key)));
        }
        System.out.println(replace);
    }
}