Leetcode1845. Seat Reservation Manager (堆的应用)

  1. Seat Reservation Manager
    Medium
    Design a system that manages the reservation state of n seats that are numbered from 1 to n.

Implement the SeatManager class:

SeatManager(int n) Initializes a SeatManager object that will manage n seats numbered from 1 to n. All seats are initially available.

int reserve() Fetches the smallest-numbered unreserved seat, reserves it, and returns its number.

void unreserve(int seatNumber) Unreserves the seat with the given seatNumber.

Example 1:

Input

"SeatManager", "reserve", "reserve", "unreserve", "reserve", "reserve", "reserve", "reserve", "unreserve"

\[5\], \[\], \[\], \[2\], \[\], \[\], \[\], \[\], \[5\]

Output

null, 1, 2, null, 2, 3, 4, 5, null

Explanation

SeatManager seatManager = new SeatManager(5); // Initializes a SeatManager with 5 seats.

seatManager.reserve(); // All seats are available, so return the lowest numbered seat, which is 1.

seatManager.reserve(); // The available seats are [2,3,4,5], so return the lowest of them, which is 2.

seatManager.unreserve(2); // Unreserve seat 2, so now the available seats are [2,3,4,5].

seatManager.reserve(); // The available seats are [2,3,4,5], so return the lowest of them, which is 2.

seatManager.reserve(); // The available seats are [3,4,5], so return the lowest of them, which is 3.

seatManager.reserve(); // The available seats are [4,5], so return the lowest of them, which is 4.

seatManager.reserve(); // The only available seat is seat 5, so return 5.

seatManager.unreserve(5); // Unreserve seat 5, so now the available seats are [5].

Constraints:

1 <= n <= 105

1 <= seatNumber <= n

For each call to reserve, it is guaranteed that there will be at least one unreserved seat.

For each call to unreserve, it is guaranteed that seatNumber will be reserved.

At most 105 calls in total will be made to reserve and unreserve.

解法1: 用set。

cpp 复制代码
class SeatManager {
public:
    SeatManager(int n) {
        for (int i = 1; i <= n; i++) {
            unreserved.insert(i);
        }
    }
    
    int reserve() {
        int num = *unreserved.begin();
        unreserved.erase(num);
        return num;
    }
    
    void unreserve(int seatNumber) {
        unreserved.insert(seatNumber);
    }
private:
    set<int> unreserved;
};

/**
 * Your SeatManager object will be instantiated and called as such:
 * SeatManager* obj = new SeatManager(n);
 * int param_1 = obj->reserve();
 * obj->unreserve(seatNumber);
 */

实际上用priority_queue更好。

cpp 复制代码
class SeatManager {
public:
    SeatManager(int n) {
        for (int i = 1; i <= n; i++) {
            minHeap.push(i);
        }
    }
    
    int reserve() {
        int num = minHeap.top();
        minHeap.pop();
        return num;
    }
    
    void unreserve(int seatNumber) {
        minHeap.push(seatNumber);
    }
private:
    priority_queue<int, vector<int>, greater<int>> minHeap;
};

/**
 * Your SeatManager object will be instantiated and called as such:
 * SeatManager* obj = new SeatManager(n);
 * int param_1 = obj->reserve();
 * obj->unreserve(seatNumber);
 */
相关推荐
程序员东岸8 小时前
《数据结构——排序(中)》选择与交换的艺术:从直接选择到堆排序的性能跃迁
数据结构·笔记·算法·leetcode·排序算法
做怪小疯子11 小时前
LeetCode 热题 100——二叉树——二叉树的层序遍历&将有序数组转换为二叉搜索树
算法·leetcode·职场和发展
CoderYanger11 小时前
递归、搜索与回溯-记忆化搜索:38.最长递增子序列
java·算法·leetcode·1024程序员节
CoderYanger12 小时前
C.滑动窗口-越短越合法/求最长/最大——2958. 最多 K 个重复元素的最长子数组
java·数据结构·算法·leetcode·哈希算法·1024程序员节
却话巴山夜雨时i13 小时前
394. 字符串解码【中等】
java·数据结构·算法·leetcode
leoufung13 小时前
LeetCode 230:二叉搜索树中第 K 小的元素 —— 从 Inorder 遍历到 Order Statistic Tree
算法·leetcode·职场和发展
惊鸿.Jh13 小时前
503. 下一个更大元素 II
数据结构·算法·leetcode
小白程序员成长日记14 小时前
2025.12.01 力扣每日一题
算法·leetcode·职场和发展
.柒宇.16 小时前
力扣hot100---42.接雨水(java版)
java·算法·leetcode