Leetcode1845. Seat Reservation Manager (堆的应用)

  1. Seat Reservation Manager
    Medium
    Design a system that manages the reservation state of n seats that are numbered from 1 to n.

Implement the SeatManager class:

SeatManager(int n) Initializes a SeatManager object that will manage n seats numbered from 1 to n. All seats are initially available.

int reserve() Fetches the smallest-numbered unreserved seat, reserves it, and returns its number.

void unreserve(int seatNumber) Unreserves the seat with the given seatNumber.

Example 1:

Input

"SeatManager", "reserve", "reserve", "unreserve", "reserve", "reserve", "reserve", "reserve", "unreserve"

\[5\], \[\], \[\], \[2\], \[\], \[\], \[\], \[\], \[5\]

Output

null, 1, 2, null, 2, 3, 4, 5, null

Explanation

SeatManager seatManager = new SeatManager(5); // Initializes a SeatManager with 5 seats.

seatManager.reserve(); // All seats are available, so return the lowest numbered seat, which is 1.

seatManager.reserve(); // The available seats are 2,3,4,5, so return the lowest of them, which is 2.

seatManager.unreserve(2); // Unreserve seat 2, so now the available seats are 2,3,4,5.

seatManager.reserve(); // The available seats are 2,3,4,5, so return the lowest of them, which is 2.

seatManager.reserve(); // The available seats are 3,4,5, so return the lowest of them, which is 3.

seatManager.reserve(); // The available seats are 4,5, so return the lowest of them, which is 4.

seatManager.reserve(); // The only available seat is seat 5, so return 5.

seatManager.unreserve(5); // Unreserve seat 5, so now the available seats are 5.

Constraints:

1 <= n <= 105

1 <= seatNumber <= n

For each call to reserve, it is guaranteed that there will be at least one unreserved seat.

For each call to unreserve, it is guaranteed that seatNumber will be reserved.

At most 105 calls in total will be made to reserve and unreserve.

解法1: 用set。

cpp 复制代码
class SeatManager {
public:
    SeatManager(int n) {
        for (int i = 1; i <= n; i++) {
            unreserved.insert(i);
        }
    }
    
    int reserve() {
        int num = *unreserved.begin();
        unreserved.erase(num);
        return num;
    }
    
    void unreserve(int seatNumber) {
        unreserved.insert(seatNumber);
    }
private:
    set<int> unreserved;
};

/**
 * Your SeatManager object will be instantiated and called as such:
 * SeatManager* obj = new SeatManager(n);
 * int param_1 = obj->reserve();
 * obj->unreserve(seatNumber);
 */

实际上用priority_queue更好。

cpp 复制代码
class SeatManager {
public:
    SeatManager(int n) {
        for (int i = 1; i <= n; i++) {
            minHeap.push(i);
        }
    }
    
    int reserve() {
        int num = minHeap.top();
        minHeap.pop();
        return num;
    }
    
    void unreserve(int seatNumber) {
        minHeap.push(seatNumber);
    }
private:
    priority_queue<int, vector<int>, greater<int>> minHeap;
};

/**
 * Your SeatManager object will be instantiated and called as such:
 * SeatManager* obj = new SeatManager(n);
 * int param_1 = obj->reserve();
 * obj->unreserve(seatNumber);
 */
相关推荐
一起努力啊~2 小时前
算法题打卡力扣第1658题:将 x 减到 0 的最小操作数(mid)
学习·leetcode
Cccp.1232 小时前
【leetcode】(六) 图和贪心算法
数据结构·算法·leetcode
y1su2 小时前
【Leetcode】1477. 找两个和为目标值且不重叠的子数组
数据结构·后端·算法·leetcode·职场和发展
mmmmath_313 小时前
LeetCode.541.反转字符串II
数据结构·算法·leetcode
Navigator_Z13 小时前
LeetCode //MySQL - 1251. Average Selling Price
c语言·算法·leetcode
参.商.15 小时前
【Day 53】76. 最小覆盖子串
leetcode·golang
虚无的纽扣17 小时前
【力扣刷题】第二天:无重复字符的最长字串、移动零问题
算法·leetcode·排序算法
圣保罗的大教堂21 小时前
leetcode 3742. 网格中得分最大的路径 中等
leetcode
我不会起名字3221 天前
一天一道算法题(35):电话号码的字母组合
java·数据结构·后端·python·leetcode·go·回溯
圣保罗的大教堂1 天前
leetcode 2033. 获取单值网格的最小操作数 中等
leetcode