代码随想录算法训练营第五十三天|309.最佳买卖股票时机含冷冻期、714.买卖股票的最佳时机含手续费
309.最佳买卖股票时机含冷冻期
状态:有难度
代码
bash
class Solution {
public:
int maxProfit(vector<int>& prices) {
int n = prices.size();
if (n == 0) return 0;
vector<vector<int>> dp(n, vector<int>(4, 0));
dp[0][0] -= prices[0]; // 持股票
for (int i = 1; i < n; i++) {
dp[i][0] = max(dp[i - 1][0], max(dp[i - 1][3] - prices[i], dp[i - 1][1] - prices[i]));
dp[i][1] = max(dp[i - 1][1], dp[i - 1][3]);
dp[i][2] = dp[i - 1][0] + prices[i];
dp[i][3] = dp[i - 1][2];
}
return max(dp[n - 1][3], max(dp[n - 1][1], dp[n - 1][2]));
}
};
714.买卖股票的最佳时机含手续费
状态:不会
代码
bash
class Solution {
public:
int maxProfit(vector<int>& prices, int fee) {
int n = prices.size();
vector<vector<int>> dp(n, vector<int>(2, 0));
dp[0][0] -= prices[0];
for (int i = 1; i < n; i++) {
dp[i][0] = max(dp[i - 1][0], dp[i - 1][1] - prices[i]);
dp[i][1] = max(dp[i - 1][1], dp[i - 1][0] + prices[i] - fee);
}
return max(dp[n - 1][0], dp[n - 1][1]);
}
};