LeetCode75——Day5

文章目录

一、题目

345. Reverse Vowels of a String

Given a string s, reverse only all the vowels in the string and return it.

The vowels are 'a', 'e', 'i', 'o', and 'u', and they can appear in both lower and upper cases, more than once.

Example 1:

Input: s = "hello"

Output: "holle"

Example 2:

Input: s = "leetcode"

Output: "leotcede"

Constraints:

1 <= s.length <= 3 * 105

s consist of printable ASCII characters.

二、题解

双指针思路,定义左指针left和右指针right

cpp 复制代码
class Solution {
public:
    string reverseVowels(string s) {
        int n = s.length();
        unordered_map<char,int> map;
        map['A'] = 1;
        map['a'] = 1;
        map['E'] = 1;
        map['e'] = 1;
        map['I'] = 1;
        map['i'] = 1;
        map['O'] = 1;
        map['o'] = 1;
        map['U'] = 1;
        map['u'] = 1;
        int left = 0;
        int right = n - 1;
        while(left < right){
            while(left < n && !map.count(s[left])) left++;
            while(right > -1 && !map.count(s[right])) right--;
            if(left < right) swap(s[left++],s[right--]);
        }
        return s;
    }
};
相关推荐
To_OC2 小时前
LC 994 腐烂的橘子:人人都说是 BFS 入门题,我却写了三遍才过
javascript·算法·leetcode
金銀銅鐵5 小时前
[Python] 扩展欧几里得算法
python·数学·算法
To_OC8 小时前
LC 200 岛屿数量:经典 DFS 入门题,我第一次写居然连方向都搞错了
javascript·算法·leetcode
郝学胜_神的一滴13 小时前
CMake 30:循环语法全解|foreach_while双循环精讲、迭代技巧与实战避坑指南
c++·cmake
To_OC1 天前
LC 128 最长连续序列:别上来就排序,O (n) 解法才是这题的灵魂
javascript·算法·leetcode
刘马想放假2 天前
Modbus 全栈技术解析:TCP、RTU、ASCII、RTU over TCP
数据结构·网络协议
05Kevin2 天前
lk每日冒险题--数据结构6.27
算法
To_OC2 天前
从一次栈溢出报错说起,我把递归彻底扒明白了
javascript·算法·程序员