在Web中搜索(Searching the Web, ACM/ICPC Beijing 2004, UVa1597)rust解法

输入n篇文章和m个请求(n<100,m≤50000),每个请求都是以下4种格式之一。

A:查找包含关键字A的文章。

A AND B:查找同时包含关键字A和B的文章。

A OR B:查找包含关键字A或B的文章。

NOT A:查找不包含关键字A的文章。

处理询问时,需要对于每篇文章输出证据。前3种询问输出所有至少包含一个关键字的行,第4种询问输出整篇文章。关键字只由小写字母组成,查找时忽略大小写。每行不超过80个字符,一共不超过1500行。

样例:

输入

复制代码
4
A manufacturer, importer, or seller of
digital media devices may not (1) sell,
or offer for sale, in interstate commerce,
or (2) cause to be transported in, or in a
manner affecting, interstate commerce,
a digital media device unless the device
includes and utilizes standard security
technologies that adhere to the security
system standards.
**********
Of course, Lisa did not necessarily
intend to read his books. She might
want the computer only to write her
midterm. But Dan knew she came from
a middle-class family and could hardly
afford the tuition, let alone her reading
fees. Books might be the only way she
could graduate
**********
Research in analysis (i.e., the evaluation
of the strengths and weaknesses of
computer system) is essential to the
development of effective security, both
for works protected by copyright law
and for information in general. Such
research can progress only through the
open publication and exchange of
complete scientific results
**********
I am very very very happy!
What about you?
**********
6
computer
books AND computer
books OR protected
NOT security
very
slick

输出

复制代码
want the computer only to write her
----------
computer system) is essential to the
==========
intend to read his books. She might
want the computer only to write her
fees. Books might be the only way she
==========
intend to read his books. She might
fees. Books might be the only way she
----------
for works protected by copyright law
==========
Of course, Lisa did not necessarily
intend to read his books. She might
want the computer only to write her
midterm. But Dan knew she came from
a middle-class family and could hardly
afford the tuition, let alone her reading
fees. Books might be the only way she
could graduate
----------
I am very very very happy!
What about you?
==========
I am very very very happy!
==========
not found
==========

解法:

rust 复制代码
use std::{
    collections::{BTreeMap, BTreeSet, HashMap},
    io,
};
#[derive(PartialEq)]
enum WordOp {
    AND,
    OR,
    None,
    NOT,
}

fn get_words(s: &String) -> Vec<String> {
    let w: String = s
        .chars()
        .map(|x| {
            if x.is_alphabetic() {
                x.to_ascii_lowercase()
            } else {
                ' '
            }
        })
        .collect();
    let wds: Vec<String> = w.split_whitespace().map(|x| x.to_string()).collect();
    wds
}
fn main() {
    let mut buf = String::new();
    io::stdin().read_line(&mut buf).unwrap();
    let n: usize = buf.trim().parse().unwrap();
    let mut articles: Vec<Vec<String>> = vec![];//每篇文章的所有行
    let mut words: Vec<HashMap<String, BTreeSet<usize>>> = vec![];//每篇文章的所有单词和单词所在的行号
    for _i in 0..n {
        let mut article: Vec<String> = vec![];
        let mut wd: HashMap<String, BTreeSet<usize>> = HashMap::new();
        loop {
            let mut buf = String::new();
            io::stdin().read_line(&mut buf).unwrap();
            if buf.trim() == "*".repeat(10) {
                break;
            }
            article.push(buf.trim().to_string());
            //count words
            let v: Vec<String> = get_words(&buf);
            let line_idx = article.len() - 1;
            for w in v.iter() {
                wd.entry(w.to_string())
                    .and_modify(|x| {
                        x.insert(line_idx);
                    })
                    .or_insert(BTreeSet::from([line_idx]));
            }
        }
        articles.push(article);
        words.push(wd);
    }
    let mut buf = String::new();
    io::stdin().read_line(&mut buf).unwrap();
    let m: usize = buf.trim().parse().unwrap();
    let mut cmds = vec![];
    for _i in 0..m {
        let mut buf = String::new();
        io::stdin().read_line(&mut buf).unwrap();
        cmds.push(buf.trim().to_string());
    }
    for cmd in cmds.iter() {
        if let Some(idx) = cmd.find("OR") {
            let word1 = cmd[0..idx - 1].to_string();
            let word2 = cmd[idx + 3..].to_string();
            find_word(&articles, &words, &word1, &word2, WordOp::OR);
        } else if let Some(idx) = cmd.find("AND") {
            let word1 = cmd[0..idx - 1].to_string();
            let word2 = cmd[idx + 4..].to_string();
            find_word(&articles, &words, &word1, &word2, WordOp::AND);
        } else if let Some(idx) = cmd.find("NOT") {
            let word1 = cmd[idx + 4..].to_string();
            find_word(&articles, &words, &word1, &"".to_string(), WordOp::NOT);
        } else {
            let word1 = cmd;
            find_word(&articles, &words, word1, &"".to_string(), WordOp::None);
        }
        println!("{}", "=".repeat(10));
    }
}

fn print_result(find_result: BTreeMap<usize, BTreeSet<usize>>, articles: &Vec<Vec<String>>) {
    if find_result.is_empty() {
        println!("not found");
    } else {
        let mut cnt = 0;
        for (k, v) in find_result.iter() {
            for i in v.iter() {
                println!("{}", articles[*k][*i]);
            }
            cnt += 1;
            if cnt != find_result.len() {
                println!("{}", "-".repeat(10));
            }
        }
    }
}

fn find_word(
    articles: &Vec<Vec<String>>,
    words: &Vec<HashMap<String, BTreeSet<usize>>>,
    word1: &String,
    word2: &String,
    op: WordOp,
) {
    let mut find_result: BTreeMap<usize, BTreeSet<usize>> = BTreeMap::new();
    for (aidx, lines) in articles.iter().enumerate() {
        let mut find_line_idx: BTreeSet<usize> = BTreeSet::new();
        let ws = words.get(aidx).unwrap();
        if op == WordOp::OR {
            if ws.contains_key(word1) || ws.contains_key(word2) {
                if let Some(idx) = ws.get(word1) {
                    find_line_idx.append(&mut idx.clone());
                }
                if let Some(idx) = ws.get(word2) {
                    find_line_idx.append(&mut idx.clone());
                }
                find_result.insert(aidx, find_line_idx);
            }
        } else if op == WordOp::AND {
            if ws.contains_key(word1) && ws.contains_key(word2) {
                let idx = ws.get(word1).unwrap();
                find_line_idx.append(&mut idx.clone());
                let idx = ws.get(word2).unwrap();
                find_line_idx.append(&mut idx.clone());
                find_result.insert(aidx, find_line_idx);
            }
        } else if op == WordOp::None {
            if ws.contains_key(word1) {
                let idx = ws.get(word1).unwrap();
                find_line_idx.append(&mut idx.clone());
                find_result.insert(aidx, find_line_idx);
            }
        } else if op == WordOp::NOT {
            if !ws.contains_key(word1) {
                find_line_idx.append(&mut (0..lines.len()).collect());
                find_result.insert(aidx, find_line_idx);
            }
        }
    }
    print_result(find_result, &articles);
}
相关推荐
alwaysrun5 小时前
Rust中所有权和作用域及生命周期
rust·生命周期·作用域·所有权·引用与借用
FleetingLore21 小时前
Rust | str 常用方法
rust
一只小松许️2 天前
深入理解 Rust 的内存模型:变量、值与指针
java·开发语言·rust
m0_480502643 天前
Rust 登堂 之 Cell 和 RefCell(十二)
开发语言·后端·rust
烈风3 天前
011 Rust数组
开发语言·后端·rust
Dontla4 天前
Turbopack介绍(由Vercel开发的基于Rust的高性能前端构建工具,用于挑战传统构建工具Webpack、vite地位)Next.js推荐构建工具
前端·rust·turbopack
开心不就得了5 天前
构建工具webpack
前端·webpack·rust
ftpeak5 天前
《WebAssembly指南》第九章:WebAssembly 导入全局字符串常量
开发语言·rust·wasm
红烧code6 天前
【Rust GUI开发入门】编写一个本地音乐播放器(15. 记录运行日志)
rust·gui·log·slint
JordanHaidee6 天前
【Rust GUI开发入门】编写一个本地音乐播放器(15. 记录运行日志)
rust