Leetcode 381. Insert Delete GetRandom O(1) - Duplicates allowed (数据结构设计好题)

  1. Insert Delete GetRandom O(1) - Duplicates allowed
    Hard

RandomizedCollection is a data structure that contains a collection of numbers, possibly duplicates (i.e., a multiset). It should support inserting and removing specific elements and also reporting a random element.

Implement the RandomizedCollection class:

RandomizedCollection() Initializes the empty RandomizedCollection object.

bool insert(int val) Inserts an item val into the multiset, even if the item is already present. Returns true if the item is not present, false otherwise.

bool remove(int val) Removes an item val from the multiset if present. Returns true if the item is present, false otherwise. Note that if val has multiple occurrences in the multiset, we only remove one of them.

int getRandom() Returns a random element from the current multiset of elements. The probability of each element being returned is linearly related to the number of the same values the multiset contains.

You must implement the functions of the class such that each function works on average O(1) time complexity.

Note: The test cases are generated such that getRandom will only be called if there is at least one item in the RandomizedCollection.

Example 1:

Input

"RandomizedCollection", "insert", "insert", "insert", "getRandom", "remove", "getRandom"

\[\], \[1\], \[1\], \[2\], \[\], \[1\], \[\]

Output

null, true, false, true, 2, true, 1

Explanation

RandomizedCollection randomizedCollection = new RandomizedCollection();

randomizedCollection.insert(1); // return true since the collection does not contain 1.

// Inserts 1 into the collection.

randomizedCollection.insert(1); // return false since the collection contains 1.

// Inserts another 1 into the collection. Collection now contains 1,1.

randomizedCollection.insert(2); // return true since the collection does not contain 2.

// Inserts 2 into the collection. Collection now contains 1,1,2.

randomizedCollection.getRandom(); // getRandom should:

// - return 1 with probability 2/3, or

// - return 2 with probability 1/3.

randomizedCollection.remove(1); // return true since the collection contains 1.

// Removes 1 from the collection. Collection now contains 1,2.

randomizedCollection.getRandom(); // getRandom should return 1 or 2, both equally likely.

Constraints:

-231 <= val <= 231 - 1

At most 2 * 105 calls in total will be made to insert, remove, and getRandom.

There will be at least one element in the data structure when getRandom is called.

解法1:注意题目的要求。每个操作(insert(), delete(), getRandom())都必须是O(1)时间复杂度。

getRandom()是O(1),那么必须用数组。

insert()和delete()是O(1),可以用doubly linked list+map,也可以直接就用unordered_set()。

cpp 复制代码
class RandomizedCollection {
public:
    RandomizedCollection() {
    }
    
    bool insert(int val) {
        bool res = false;
        if (val2freq.find(val) == val2freq.end()) res = true;
        val2freq[val]++;
        data.push_back(val);
        val2index[val].insert(data.size() - 1);
        return res;
    }
    
    bool remove(int val) {
        if (val2freq.find(val) == val2freq.end()) {
            return false;
        }
        int remove_elem_index = *val2index[val].begin();
        int last_elem = data.back();
        if (last_elem != val) {
            val2index[last_elem].erase(data.size() - 1);
            val2index[last_elem].insert(remove_elem_index);
            val2index[val].erase(remove_elem_index);
            data[remove_elem_index] = last_elem;
        }
        data.pop_back();
        val2freq[val]--;
        if (val2freq[val] == 0) {
            val2freq.erase(val);
            val2index.erase(val);
        }
        return true;
    }
    
    int getRandom() {
        return data[random() % data.size()];
    }
private:
    unordered_map<int, int> val2freq; //<value, freq>
    //unordered_map<int, vector<int>> val2index; //<value, indexes>
    unordered_map<int, unordered_set<int>> val2index; //<value, indexes>
    vector<int> data;    
};

/**
 * Your RandomizedCollection object will be instantiated and called as such:
 * RandomizedCollection* obj = new RandomizedCollection();
 * bool param_1 = obj->insert(val);
 * bool param_2 = obj->remove(val);
 * int param_3 = obj->getRandom();
 */
相关推荐
祖力5513 小时前
数据结构的基本概念与单向链表(链表数据类型构造、创建、头插、尾插、头删、尾删)
数据结构·链表
大明者省15 小时前
WSL2 Ubuntu22.04 GPU训练环境配置指南
人工智能·算法·计算机视觉
白狐_79816 小时前
408数据结构第8章:排序②——性质对比秒杀、场景选择与外部排序
java·数据结构·算法
zander25817 小时前
LeetCode 84:柱状图中的最大矩形——单调栈如何确定左右边界
java·数据结构·算法
Shell运维手记17 小时前
Linux 常用基础命令学习笔记
linux·运维·笔记·学习·算法·github
杨航 AI17 小时前
O(n log n):线性对数原理拆解 这个是排序算法的黄金复杂度之一。
算法·排序算法
船厂电气自动化ai大模型18 小时前
AI大模型与数学 第32课 函数凹凸性与二阶导数:拐点求解、凹凸区间计算(10道二阶导数计算题)
数据结构·人工智能·python·深度学习·算法
旖旎夜光18 小时前
LeetCode 3:无重复字符的最长子串(滑动窗口) —— 题解
数据结构·c++·算法·leetcode·滑动窗口
叠层归一研究院19 小时前
AGI 系统(十一):二阶网络 — 二阶递归 × 多主体 (元符号网络)
开发语言·人工智能·算法·php·agi
zlinear数据采集卡20 小时前
D223的PWM电机控制:6路独立脉冲+加减速算法深度解析
arm开发·stm32·嵌入式硬件·算法·fpga开发·架构