Leetcode 381. Insert Delete GetRandom O(1) - Duplicates allowed (数据结构设计好题)

  1. Insert Delete GetRandom O(1) - Duplicates allowed
    Hard

RandomizedCollection is a data structure that contains a collection of numbers, possibly duplicates (i.e., a multiset). It should support inserting and removing specific elements and also reporting a random element.

Implement the RandomizedCollection class:

RandomizedCollection() Initializes the empty RandomizedCollection object.

bool insert(int val) Inserts an item val into the multiset, even if the item is already present. Returns true if the item is not present, false otherwise.

bool remove(int val) Removes an item val from the multiset if present. Returns true if the item is present, false otherwise. Note that if val has multiple occurrences in the multiset, we only remove one of them.

int getRandom() Returns a random element from the current multiset of elements. The probability of each element being returned is linearly related to the number of the same values the multiset contains.

You must implement the functions of the class such that each function works on average O(1) time complexity.

Note: The test cases are generated such that getRandom will only be called if there is at least one item in the RandomizedCollection.

Example 1:

Input

"RandomizedCollection", "insert", "insert", "insert", "getRandom", "remove", "getRandom"

\[\], \[1\], \[1\], \[2\], \[\], \[1\], \[\]

Output

null, true, false, true, 2, true, 1

Explanation

RandomizedCollection randomizedCollection = new RandomizedCollection();

randomizedCollection.insert(1); // return true since the collection does not contain 1.

// Inserts 1 into the collection.

randomizedCollection.insert(1); // return false since the collection contains 1.

// Inserts another 1 into the collection. Collection now contains 1,1.

randomizedCollection.insert(2); // return true since the collection does not contain 2.

// Inserts 2 into the collection. Collection now contains 1,1,2.

randomizedCollection.getRandom(); // getRandom should:

// - return 1 with probability 2/3, or

// - return 2 with probability 1/3.

randomizedCollection.remove(1); // return true since the collection contains 1.

// Removes 1 from the collection. Collection now contains 1,2.

randomizedCollection.getRandom(); // getRandom should return 1 or 2, both equally likely.

Constraints:

-231 <= val <= 231 - 1

At most 2 * 105 calls in total will be made to insert, remove, and getRandom.

There will be at least one element in the data structure when getRandom is called.

解法1:注意题目的要求。每个操作(insert(), delete(), getRandom())都必须是O(1)时间复杂度。

getRandom()是O(1),那么必须用数组。

insert()和delete()是O(1),可以用doubly linked list+map,也可以直接就用unordered_set()。

cpp 复制代码
class RandomizedCollection {
public:
    RandomizedCollection() {
    }
    
    bool insert(int val) {
        bool res = false;
        if (val2freq.find(val) == val2freq.end()) res = true;
        val2freq[val]++;
        data.push_back(val);
        val2index[val].insert(data.size() - 1);
        return res;
    }
    
    bool remove(int val) {
        if (val2freq.find(val) == val2freq.end()) {
            return false;
        }
        int remove_elem_index = *val2index[val].begin();
        int last_elem = data.back();
        if (last_elem != val) {
            val2index[last_elem].erase(data.size() - 1);
            val2index[last_elem].insert(remove_elem_index);
            val2index[val].erase(remove_elem_index);
            data[remove_elem_index] = last_elem;
        }
        data.pop_back();
        val2freq[val]--;
        if (val2freq[val] == 0) {
            val2freq.erase(val);
            val2index.erase(val);
        }
        return true;
    }
    
    int getRandom() {
        return data[random() % data.size()];
    }
private:
    unordered_map<int, int> val2freq; //<value, freq>
    //unordered_map<int, vector<int>> val2index; //<value, indexes>
    unordered_map<int, unordered_set<int>> val2index; //<value, indexes>
    vector<int> data;    
};

/**
 * Your RandomizedCollection object will be instantiated and called as such:
 * RandomizedCollection* obj = new RandomizedCollection();
 * bool param_1 = obj->insert(val);
 * bool param_2 = obj->remove(val);
 * int param_3 = obj->getRandom();
 */
相关推荐
longlongzihan1 天前
LeetCode 17电话号码的字母组合:回溯算法(DFS)详解
c++·算法·leetcode·深度优先
封印师请假去地球钓鱼1 天前
边解边变的问题:从“决策依赖“一词出发
人工智能·算法
今晚打老虎1 天前
c++之提高A(前缀和)(第三课)
数据结构·c++·算法
不会就选b1 天前
算法日常・每日刷题--<贪心>26
数据结构·算法
hetao17338371 天前
2026-09-29 hetao1733837 的刷题记录
c++·算法
欣欣之王来了1 天前
AI合规专项:AI算法透明度的合规要求
人工智能·算法
wzdark1 天前
分块思想在算法优化中的实践与应用4
算法
Because_of_Her11 天前
dfs-洪水填充技巧
笔记·算法·深度优先·洪水填充
小静AI工程实验室1 天前
RSA 算法详解:从模幂原理到 OAEP 加密、PSS 签名与 Python 实验
python·算法
xzal121 天前
GESP Python笔记
笔记·python·算法