133.克隆图
本题就是遍历整个图,遍历的时候要记录已经访问过的节点
方法一:深度优先搜索
java
/*
// Definition for a Node.
class Node {
public int val;
public List<Node> neighbors;
public Node() {
val = 0;
neighbors = new ArrayList<Node>();
}
public Node(int _val) {
val = _val;
neighbors = new ArrayList<Node>();
}
public Node(int _val, ArrayList<Node> _neighbors) {
val = _val;
neighbors = _neighbors;
}
}
*/
class Solution {
HashMap<Node,Node> visited = new HashMap<>();
public Node cloneGraph(Node node) {
if(node == null){
return node;
}
//如果该节点已经被访问过,则直接从哈希表中取出对应的克隆节点返回
if(visited.containsKey(node)){
return visited.get(node);
}
//克隆节点,注意到为了深拷贝不会克隆他的邻居列表
Node cloneNode = new Node(node.val,new ArrayList());
//哈希表存储
visited.put(node,cloneNode);
//遍历该节点的邻居并更新克隆节点的邻居列表
for(Node neighbor : node.neighbors){
cloneNode.neighbors.add(cloneGraph(neighbor));
}
return cloneNode;
}
}
方法二:广度优先搜索
java
/*
// Definition for a Node.
class Node {
public int val;
public List<Node> neighbors;
public Node() {
val = 0;
neighbors = new ArrayList<Node>();
}
public Node(int _val) {
val = _val;
neighbors = new ArrayList<Node>();
}
public Node(int _val, ArrayList<Node> _neighbors) {
val = _val;
neighbors = _neighbors;
}
}
*/
class Solution {
public Node cloneGraph(Node node) {
if(node == null){
return node;
}
HashMap<Node,Node> visited = new HashMap<>();
//将给定的节点添加到队列
LinkedList<Node> queue = new LinkedList<Node>();
queue.add(node);
//克隆第一个节点并存储到哈希表中
visited.put(node,new Node(node.val,new ArrayList()));
//广度优先搜索
while(!queue.isEmpty()){
//取出队列的头结点
Node n = queue.remove();
//遍历该节点的邻居
for(Node neighbor : n.neighbors){
if(!visited.containsKey(neighbor)){
//如果没有被访问,就克隆并存储到哈希表
visited.put(neighbor,new Node(neighbor.val,new ArrayList()));
//将邻居节点添加到队列中
queue.add(neighbor);
}
//更新当前节点的邻居列表
visited.get(n).neighbors.add(visited.get(neighbor));
}
}
return visited.get(node);
}
}