Postgresql 表结构、列名相关信息查询

查询数据库拥有的表数量

sql 复制代码
select count(*)
from pg_class c join pg_namespace n on relnamespace = n.oid where relkind = 'r' and n.nspname = 'public' ;

查询所有表名及注释

sql 复制代码
-- 方法一
select relname, reltuples as rw,obj_description(c.oid)
from pg_class c join pg_namespace n on relnamespace = n.oid where relkind = 'r' and n.nspname = 'public';

-- 方法二 加条件 and relchecks=0是过滤掉分表
SELECT relname as tabname,
    cast(obj_description(relfilenode,'pg_class') as varchar) as comment 
FROM pg_class c 
WHERE relchecks=0 
AND relkind = 'r' 
AND relname not like 'pg_%' 
AND relname not like 'sql_%'
order by relname;

查询字段名、类型、注释、是否为空

sql 复制代码
SELECT 
    col_description(a.attrelid,a.attnum) as comment,
    format_type(a.atttypid,a.atttypmod) as type,
    a.attname as name, 
    a.attnotnull as notnull   
FROM pg_class as c,pg_attribute as a 
where c.relname = '表名' 
and a.attrelid = c.oid 
and a.attnum>0;

查询表字段(详细版):列名、备注、类型、是否为空、长度、是否为主键

sql 复制代码
select a.attname as colname,	col_description(a.attrelid,a.attnum) as remarks,t.typname,a.attnotnull as notnull ,
(case when atttypmod-4>0 then atttypmod-4 else 0 end) len,
(case  when (select count(*) from pg_constraint where conrelid = a.attrelid and conkey[1]=attnum and contype='p')>0  
	then 'Y' else 'N' end) as primarykey
from pg_attribute a left join pg_class c on a.attrelid = c.oid
left join pg_type t on a.atttypid = t.oid
where	a.attnum >= 0 and c.relname = '表名'
order by c.relname desc,	a.attnum asc

查询表和表字段(表名和列的详细信息的融合)

sql 复制代码
select ROW_NUMBER() over(ORDER bY c.relname ,	a.attnum asc ) AS	 num,
 c.relname as 英文表名,
 de.description  as 中文表名,
a.attname as 英文字段名称,	
col_description(a.attrelid,a.attnum) as 中文字段名称,
t.typname 字段类型,
(case when atttypmod-4>0 then atttypmod-4 else 0 end) 字段长度,
'0' 字段小数位数,
(case when a.attnotnull='t' THEN	'是' ELSE	'否' END )  字段是否非空,
(case  when (select count(*) from pg_constraint where conrelid = a.attrelid 
and conkey[1]=attnum and contype='p')>0  	then '是' else '否' end)  字段是否主键,
'该字段为'||col_description(a.attrelid,a.attnum) as 字段描述
from pg_attribute a 
left join pg_class c on a.attrelid = c.oid
left join pg_type t on a.atttypid = t.oid
left outer join pg_namespace pn on c.relnamespace = pn.oid
left join ( select pd.*
    from pg_description pd
    where 1=1
        and pd.objsubid = 0 ) de on c.oid = de.objoid 
where	a.attnum >= 0 
and relchecks=0 
and relkind in ('r','v','m','f','p')
and pn.nspname not in ('pg_catalog','information_schema') 
        and pn.nspname not like 'pg_toast%'
order by c.relname ,	a.attnum asc;
相关推荐
后端小张1 小时前
Redis 执行 Lua,能保证原子性吗?
数据库·redis·缓存
离开地球表面_991 小时前
索引失效?查询结果不正确?原来都是隐式转换惹的祸
数据库·后端·mysql
lipviolet1 小时前
Redis系列---Redission分布式锁
数据库·redis·分布式
Zhen (Evan) Wang1 小时前
.NET 6 API + Dapper + SQL Server 2014
数据库·c#·.net
毕设木哥2 小时前
25届计算机专业毕设选题推荐-基于python+Django协调过滤的新闻推荐系统
大数据·服务器·数据库·python·django·毕业设计·课程设计
洛阳泰山2 小时前
Llamaindex 使用过程中的常见问题 (FAQ)
java·服务器·数据库·python·llm·rag·llamaindex
没有名字的小羊2 小时前
Linux基础命令——账户简单管理
linux·运维·服务器·网络·数据库
单字叶2 小时前
MySQL数据库管理
数据库·mysql
ID_云泽3 小时前
MVCC机制解析:提升数据库并发性能的关键
数据库·mvcc
小灰灰是码农...3 小时前
MySQL的数据库课程设计的基本步骤和考虑因素
数据库